a. Calculate the standard enthalpy of formation of carbon disulphide (CS₂) from its elements, given that C(graphite) + 2 S(rhombic) → CS2(1) C(graphite) + O2(g) → CO2(g) AHxn -393.5 kJ/mol SO2(g) -296.4 kJ/mol S(rhombic) + O2(g) rxn ΔΗ, AH rxn CS2(0)+ 3 O2(g) + CO2(g) +2 SO2(g) = -1073.6 kJ/mol 300

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Chapter1: Chemical Foundations
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a. Calculate the standard enthalpy of formation of carbon disulphide (CS₂) from its
elements, given that
C(graphite) + 2 S(rhombic) → CS2(1)
→ CO2(g)
(a)
C(graphite) + O2(g)
AH° rxn = -393.5 kJ/mol
(b)
AH rxn = -296.4 kJ/mol
S(rhombic) + O2(g)
SO2(g)
(c)
CS2(0)+ 3 O2(g)
→ CO2(g) +2 SO2(g)
=
ΔΗ,
AHºrn -1073.6 kJ/mol
b. From the following data,
(a) C(graphite) + O2(g)
CO2(g)
-393.5 kJ/mol
(b) H2(g) + 1/2O2(g) → H₂O(1)
-285.8 kJ/mol
-3119.6 kJ/mol
(c)2 C₂H2(g) + 7 O2(g) → 4CO2(g) + 6 H₂O(1)
Calculate the enthalpy change for the reaction
C. Calculate the standard enthalpy change for the reaction
2Al(s) + Fe2O3(s) → 2Fe(s) + Al2O3(s)
given that
(a)
(b)
AH rxn
ΔΗ,
AHºrxn
2 C(graphite) + 3 H2(g) → C₂H6(g)
2Al(s) + 3/2O2(g) →Al2O3(s)
2Fe(s) + 3/2 O2 (g) → Fe2O3(s)
=
AHOrxn=-1669.8 kJ/mol
AHOrxn-822.2 kJ/mol
=
Transcribed Image Text:a. Calculate the standard enthalpy of formation of carbon disulphide (CS₂) from its elements, given that C(graphite) + 2 S(rhombic) → CS2(1) → CO2(g) (a) C(graphite) + O2(g) AH° rxn = -393.5 kJ/mol (b) AH rxn = -296.4 kJ/mol S(rhombic) + O2(g) SO2(g) (c) CS2(0)+ 3 O2(g) → CO2(g) +2 SO2(g) = ΔΗ, AHºrn -1073.6 kJ/mol b. From the following data, (a) C(graphite) + O2(g) CO2(g) -393.5 kJ/mol (b) H2(g) + 1/2O2(g) → H₂O(1) -285.8 kJ/mol -3119.6 kJ/mol (c)2 C₂H2(g) + 7 O2(g) → 4CO2(g) + 6 H₂O(1) Calculate the enthalpy change for the reaction C. Calculate the standard enthalpy change for the reaction 2Al(s) + Fe2O3(s) → 2Fe(s) + Al2O3(s) given that (a) (b) AH rxn ΔΗ, AHºrxn 2 C(graphite) + 3 H2(g) → C₂H6(g) 2Al(s) + 3/2O2(g) →Al2O3(s) 2Fe(s) + 3/2 O2 (g) → Fe2O3(s) = AHOrxn=-1669.8 kJ/mol AHOrxn-822.2 kJ/mol =
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