Apply Hess's law to calculate the energy for the combustion of methanol. CH3OH) + 02(9) --> CO2(9) + H2O9) The necessary enthalpy of formation at standard conditions for each of the compounds are given below. You must balance the reaction before you do your calculations CH3OH) = -238.7 kJ/mol CO2(9) = -393.5 kJ/mol %3D H20(G) = -241.8 kJ/mol O a. + 396.6 kJ O b. -638.4 kJ O c. +638.4 kJ O d. -396.6 kJ

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Apply Hess's law to calculate the energy for the combustion of methanol.
CH3OH() + O2(g) --> CO2(9) + H20(g)
The necessary enthalpy of formation at standard conditions for each of the compounds
are given below. You must balance the reaction before you do your calculations
CH3OH) = -238.7 kJ/mol
%3D
CO2(g) = -393.5 kJ/mol
H20(g) = -241.8 kJ/mol
%3D
O a. + 396.6 kJ
O b. -638.4 kJ
O c. +638.4 kJ
O d. -396.6 kJ
Transcribed Image Text:Apply Hess's law to calculate the energy for the combustion of methanol. CH3OH() + O2(g) --> CO2(9) + H20(g) The necessary enthalpy of formation at standard conditions for each of the compounds are given below. You must balance the reaction before you do your calculations CH3OH) = -238.7 kJ/mol %3D CO2(g) = -393.5 kJ/mol H20(g) = -241.8 kJ/mol %3D O a. + 396.6 kJ O b. -638.4 kJ O c. +638.4 kJ O d. -396.6 kJ
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