A Z-test for single population mean is conducted with Ha: µ < 10, at significance level of 0.05, The most significant result is suggested by the following test statistic O -1.65 O2.2 4.7 O 1.96 O3.7 O -4.5
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- A manager of a pizza restaurant has changed the restaurant's delivery process in an effort to reduce the mean time between the order and completion of delivery from the current 30 minutes. A sample of 49 orders using the new delivery process yields a sample mean of 27.8 minutes and a sample standard deviation of 5 minutes. Complete parts (a) through (d) below. a. Using the critical value approach, at the 0.01 level of significance, is there evidence that the population mean delivery time has been reduced below the previous population mean value of 30 minutes? State the null and alternative hypotheses for this test. O A. Ho: H5 30 H: u> 30 Ο Β . Ho: με 27.8 O c. H μ2 30 H: u 30 OF. Ho: H 27.8 H,: us 30 H,: µ2 30 What is the test statistic for this test? ISTAT =O (Type an integer or a decimal. Round to two decimal places as needed.) What is(are) the critical value(s) for this test? (Type an integer or a decimal. Round to two decimal places as needed. Use commas to separate your answers…8. 140 migrating pigeons were caught by a biologist for data collection. The mass of these pigeons is normally distributed with mean 0.9 kg and standard deviation of deviation 0.15 kg. a) Determine the percentile rank of a pigeon weighing 1kg. b) What proportions of pigeons have weight greater than 1.1 kg or less than 0.7 Kg 31An ANOVA is used to evaluate the mean difference among three treatment conditions with a sample of n= 12 particpantsin each treatment. For study, what is df total?
- Determine the critical value for a right tailed test of a population mean at the a=0.001 level of significance with 15 degrees of fredom.In a test of weight loss programs, 111 subjects were divided such that 37 subjects followed each of 3 diets. Each was weighed a year after starting the diet and the results are in the ANOVA table below. Use a 0.05 significance level to test the claim that the mean weight loss is the same for the different diets. Source of Variation Between Groups Within Groups Total P-value 25.38918 0.8127 0.446353 F crit 3.080387 df MS F 50.778 3373.977 3424.755 2 108 31.24053 110 Should the null hypothesis that all the diets have the same mean weight loss be rejected? O A. Yes, because the P-value is greater than the significance level. O B. No, because the P-value is greater than the significance level. OC. No, because the P-value is less than the significance level. O D. Yes, because the P-value is less than the significance level.In its Fuel Economy Guide for 2016 model vehicles, the Environmental Protection Agency provides data on 11701170 vehicles. There are a number of high outliers, mainly hybrid gas‑electric vehicles. If we ignore the vehicles identified as outliers, however, the combined city and highway gas mileage of the other 11461146 vehicles is approximately Normal with mean 23.0 miles per gallon (mpg) and standard deviation 4.9 mpg. The quartiles of any distribution are the values with cumulative proportions 0.25 and 0.75 They span the middle half of the distribution. What is the first quartile of the distribution of gas mileage? What is the third quartile of the distribution of gas mileage?
- In tests of a computer component, it is found that the mean time between failures is 909 hours. A modification is made which is supposed to increase reliability by increasing the time between failures. Tests on a sample of 25 modified components produce a mean time between failures of 955 hours. Using a 1% level of significance, perform a hypothesis test to determine whether the mean time between failures for the modified components is greater than 909 hours. Assume that the population standard deviation is 53 hours.The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a α=0.05 level of significance. Give answer to at least 4 decimal places. Hours 48 41 60 55 48 68 53 55 50 49 54 52 What are the correct hypotheses? H0: hours Ha: hoursOne important consideration in determining which location is best for a new retail business is the amount of traffic that passes the location each business day. Counters are placed at each of four locations on the five weekdays, and the number of cars passing each location is recorded in the table below. At 0.05 level of significance, is there sufficient evidence of a significant difference in the mean number of cars per day at the four locations?Using MS Excel,what is the computed value of the F statistic ? * Location II II IV 45 48 44 39 50 60 50 49 39 40 38 39 44 45 42 40 42 43 44 43 0.76 2.23 1.19 0.84
- A random sample of 100 recorded deaths in United States during the past year showed that an average lifespan of 70.8 years. Assuming a population standard deviation of 8.7 years, does this deem to indicate that the mean lifespan today is greater than 70 years? Use a 0.05 level of significance.Facebook: A study showed that two years ago, the mean time spent per visit to Facebook was 20.8 minutes, Assume the standard devlation is o= 8.0 minutes. Suppose that a simple random sample of 107 visits was selected this year and has a sample mean of x= 18.8 minutes. A social scientist is interested to know whether the mean time of Facebook visits has decreased. Use the a=0.10 level of significance and the critical value method with the table. (a) State the appropriate null and alternate hypotheses. (b) Compute the value of the test statistic. (c) State a conclusion. Use the a = 0.10 level of significance.In an automobile repair and service industry, the average number of defective items in all the lots of automobile parts produced by a machine last week was 8. The supervisor believes that the mean number of defective parts produced by the same machine will differ in the present week. To test whether the average differs from 8, he samples 30 lots to obtain the mean number of defective parts to be 9 with a standard deviation of 3.Using the critical value approach, identify the decision at the 5% level of significance. Group of answer choices The decision is not to reject H0 because the test statistic does not fall in the rejection region (-∞,-1.960] U [1.960, ∞). The decision is to reject H0 because the test statistic falls in the rejection region (-∞,-1.645]. The decision is not to reject H0 because the test statistic does not fall in the rejection region [1.645, ∞). The decision is not to reject H0 because the test statistic does not fall in the rejection region (-∞,-1.645] U…