In tests of a computer component, it is found that the mean time between failures is 920 hours. A modification Is made which iS supposed to increase reliability by increasing the time between failures. Tests on a sample of 36 modified components produce a mean time between failures of 966 hours. Using a 5% level of significance, perform a hypothesis test to determine whether the mean time between failures for the modified components is greater than 920 hours. Assume that the population standard deviation is 51 hours. Ho : u>966 hours H: u= 966 hours OTest statistic : z= 108.24 Critical value :z=2.33 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. Ho : u = 966 hours H:u> 966 hours O Test statistic : z=5.41 Critical value :z=1.65 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. H:u=920 hours H:u>920 hours
In tests of a computer component, it is found that the mean time between failures is 920 hours. A modification Is made which iS supposed to increase reliability by increasing the time between failures. Tests on a sample of 36 modified components produce a mean time between failures of 966 hours. Using a 5% level of significance, perform a hypothesis test to determine whether the mean time between failures for the modified components is greater than 920 hours. Assume that the population standard deviation is 51 hours. Ho : u>966 hours H: u= 966 hours OTest statistic : z= 108.24 Critical value :z=2.33 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. Ho : u = 966 hours H:u> 966 hours O Test statistic : z=5.41 Critical value :z=1.65 Reject the null hypothesis. There is sufficient evidence to support the claim that, for the modified components, the mean time between failures is greater than 966 hours. H:u=920 hours H:u>920 hours
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![In tests of a computer component, it is found that the mean time between failures is 920 hours. A modification is made which is supposed to increase reliability
by increasing the time between failures. Tests on a sample of 36 modified components produce a mean time between failures of 966 hours. Using a 5% level of
significance, perform a hypothesis test to determine whether the mean time between failures for the modified components is greater than 920 hours. Assume
that the population standard deviation is 51 hours.
H,: u>966 hours
H: u=966 hours
O Test statistic : z= 108.24
Critical value : z=2.33
Reject the null hypothesis. There is sufficient evidence to support the claim that, for
the modified components, the mean time between failures is greater than 966 hours.
H:u= 966 hours
H: µ> 966 hours
O Test statistic : z= 5.41
Critical value : z= 1.65
Reject the null hypothesis. There is sufficient evidence to support the claim that, for
the modified components, the mean time between failures is greater than 966 hours.
Ho: u=920 hours
H: u>920 hours
O Test statistic: z 5.41
Critical value : z=1.65
Reject the null hypothesis. There is sufficient evidence to support the claim that, for
the modified components, the mean time between failures is greater than 920 hours.
H: u> 966 hours
H: u= 966 hours
OTest statistic : z=5.41
Critical value:z=2.33
Reject the null hypothesis. There is sufficient evidence to support the claim that, for
the modified components, the mean time between failures is greater than 966 hours.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98340a41-7444-4b4c-8f76-24b8a080ff45%2F64305f6d-33aa-47e8-8217-c72017d91e85%2F18mp4p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In tests of a computer component, it is found that the mean time between failures is 920 hours. A modification is made which is supposed to increase reliability
by increasing the time between failures. Tests on a sample of 36 modified components produce a mean time between failures of 966 hours. Using a 5% level of
significance, perform a hypothesis test to determine whether the mean time between failures for the modified components is greater than 920 hours. Assume
that the population standard deviation is 51 hours.
H,: u>966 hours
H: u=966 hours
O Test statistic : z= 108.24
Critical value : z=2.33
Reject the null hypothesis. There is sufficient evidence to support the claim that, for
the modified components, the mean time between failures is greater than 966 hours.
H:u= 966 hours
H: µ> 966 hours
O Test statistic : z= 5.41
Critical value : z= 1.65
Reject the null hypothesis. There is sufficient evidence to support the claim that, for
the modified components, the mean time between failures is greater than 966 hours.
Ho: u=920 hours
H: u>920 hours
O Test statistic: z 5.41
Critical value : z=1.65
Reject the null hypothesis. There is sufficient evidence to support the claim that, for
the modified components, the mean time between failures is greater than 920 hours.
H: u> 966 hours
H: u= 966 hours
OTest statistic : z=5.41
Critical value:z=2.33
Reject the null hypothesis. There is sufficient evidence to support the claim that, for
the modified components, the mean time between failures is greater than 966 hours.
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