1) A university is preparing to repopulate its dorms for the start of the semester while apandemic rages. The university wishes to provide as much testing/screening of theincoming students as possible, but is limited financially, so they are unable to test all thestudents all the time. The university can afford to conduct 60 tests per week per dorm.The testing being used identifies the virus in saliva samples (PCR amplification of viralDNA).Describe how would you setup a testing protocol for a dorm that has 10 floors, and 40students per floor (2 students per dorm room)?What type of sampling plan best describes the testing plan that you devised?

Given information: Given that the university wishes to provide as much testing/screening of the…

Answered: A university is preparing to repopulate…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a M/M/1 model, the average number of customers in the system is 16, and the average waiting time in the system (i.e., response time) is 53 minutes. Then, the average service time (in minutes) is 03.3125 03.11769 00.32075 00.30189
Do lizards play a role in spreading plant seeds? Some research carried out in a country would suggest so. The researchers collected 400 seeds of this particular type of fig, 100 of which were from each treatment: lizard dung, bird dung, rock hyrax dung, and uneaten figs. They planted these seeds in batches of 5, and for each group of 5 they recorded how many of the seeds germinated. This resulted in 20 observations for each treatment. The treatment means and standard deviations are given in the accompanying table. Treatment n Uneaten figs 20 2.80 0.30 Lizard dung 20 2.75 0.37 Bird dung 20 2.10 0.35 Hyrax dung 20 1.85 0.26 n USE SALT (a) Construct the appropriate ANOVA table, and test the hypothesis that there is no difference between the means for the number of seeds germinating for the four treatments. (Use a = 0.05. Round your mean squares to three decimal places and F statistic to two decimal places.) Source of Sum of Mean df Variation Squares Square Treatments 3 26.25 8.750 83.93…
There is no cure for the common cold, but many cold remedies claim to make you feel better faster. A consumer watch group decides to compare the effectiveness of Vitamin C to the effectiveness of Echinacea in lessening the duration of the common cold. Sixty participants have volunteered to be infected with the cold virus for this study. In addition to the Vitamin C and Echinacea treatments which will be administered in capsules that are identical in appearance, one of the researchers suggests that they add a group that receives no treatment but receives an identical looking capsule with an inactive ingredient. If they decide not to add a group that receives no treatment, then: (A) This study will not be an experiment since there will not be a control group. (B) Even if there is a difference in recovery time between the Vitamin C and Echinacea groups, we will not know if the recovery times are less than if no treatment were given. (C) The experimental design will not be taking into…
It has been observed that some persons who suffer renal failure, again suffer renal failure within one year of the first episode. This is due, in part, to damage from the first episode. The performance of a new drug designed to prevent a second episode is to be tested for its effectiveness in preventing a second episode. In order to do this two groups of people suffering a first episode are selected. There are 45 people in the first group and this group will be administered the new drug. There are 75 people in the second group and this group will be administered a placebo. After one year, 12% of the first group has a second episode and 14% of the second group has a second episode. Conduct a hypothesis test to determine, at the significance level 0.1, whether there is reason to believe that the true percentage of those in the first group who suffer a second episode is less than the true percentage of those in the second group who suffer a second episode? Select the [Rejection Region,…
A person with tuberculosis is given a chest x-ray. Four tuberculosis x-ray specialists examine each x-ray independently. If each specialist can detect tuberculosis 83% of the time when it is present, what is the probabilty that at least 1 of the specialists will detect a person positive.
It has been observed that some persons who suffer renal failure, again suffer renal failure within one year of the first episode. This is due, in part, to damage from the first episode. The performance of a new drug designed to prevent a second episode is to be tested for its effectiveness in preventing a second episode. In order to do this two groups of people suffering a first episode are selected. There are 55 people in the first group and this group will be administered the new drug. There are 75 people in the second group and this group will be administered a placebo. After one year, 10% of the first group has a second episode and 9% of the second group has a second episode. Conduct a hypothesis test to determine, at the significance level 0.01, whether there is reason to believe that the true percentage of those in the first group who suffer a second episode is different from the true percentage of those in the second group who suffer a second episode? Select the [Alternative…
Can someone explain to me what I may have done wrong on this question? A national newspaper reported that 10% of Americans have received the vaccine for Covid-19 (as of February 10, 2021). A local community is concerned that their citizens are not being vaccinated at the same rate as the rest of the nation. In a random sample of 150 residents of this community, 8% have received the vaccine. Is there significant evidence that this community’s rate of vaccination is lower than the nation’s? Test an appropriate hypothesis and state your conclusion. (Make sure to check any necessary conditions and to state a conclusion in the context of the problem.) Ho: p = .1 Ha: p < .1 p-hat (sample proportion) = 0.08, n = 150 n*p-hat = 150*0.08 = 12 and n(1-p-hat) = 150*0.92 = 138 sample is random, sample size is less than 10 percent of the population 0.08-0.1/sqrt(0.1)(.9)/150 = -.82 Was your test one-tail upper tail, one-tail lower tail, or two-tail? Explain why you chose that kind of…
A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 44 specimens and counts the number of seeds in each. Use her sample results (mean = 68.2, standard deviation = 18.5) to find the 98% confidence interval for the number of seeds for the species. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places.
It has been observed that some persons who suffer colitis, again suffer colitis within one year of the first episode. This is due, in part, to damage from the first episode. The performance of a new drug designed to prevent a second episode is to be tested for its effectiveness in preventing a second episode. In order to do this two groups of people suffering a first episode are selected. There are 170 people in the first group and this group will be administered the new drug. There are 132 people in the second group and this group wil be administered a placebo. After one year, 14% of the first group has a second episode and 18% of the second group has a second episode. What is a 90% confidence interval for the difference in true proportion of the two groups/
Beryllium is an extremely lightweight metal that is used in many industries, such as aerospace and electronics. Long-term exposure to beryllium can cause people to become sensitized. Once an individual is sensitized, continued exposure can result in chronic beryllium disease, which involves scarring of the lungs. In a study of the effects of exposure to beryllium, workers were categorized by their duration of exposure (in years) and by their disease status (diseased, sensitized, or normal). The results were as follows: Duration of Exposure <1 1 to <5 ≥5 Diseased 14 13 18 Sensitized 11 20 15 Normal 78 140 209 Test the hypothesis of independence. Use the a=0.10 level of significance and the P-value method with the TI-84 Plus calculator. What do you conclude? State the null and alternate hypotheses.
Calcium is the most abundant mineral in the human body and has several important functions. Most of the body calcium is stored in the bones and teeth, where it functions to support their structure. Recommendations for calcium are provided in Dietary Reference Intakes, developed by the Institute of Medicine of the National Academy of Sciences. The recommended adequate intake (RAI) for calcium for adults (ages 19-50) is 1000 mg per day. A random sample of 18 adults with incomes below the poverty level gave the following calcium intakes:886 633 943 847 934 8411193 820 774 834 1050 10581192 975 1313 872 1079 809Assume the population standard deviation for daily calcium intake for adults with incomes below the poverty level is 188mg.At the 0.05 level of significance, does the data provided above provide evidence to suggest that the mean calcium intake of all adults with incomes below the poverty level is less than the RAI pf 1000mg per day? Step 1: Define the parameter & setup the…
Imagine you work for a large company that sells a variety of cleaning supplies deigned to prevent the spread of viruses. You decide to investigate what the best method for preventing the spread of viruses is, if only one method is used. You design experiments with the following groups: hand sanitizer only, hand washing without soap, hand washing with soap, along with a control group. Each group has 181 observations during testing, beginning with a certain amount of the viruses present before treatment is applied. The amount of germs is being measured. You find a sum of squares between treatments of 578.59, along with a sum of squares error of 5022.05. Using this information, what is the F-statistic of your analysis?

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