A uniform rod is set up so that it can rotate about an axis at perpendicular to one of its ends. The length and mass of the rod are 0.769 m and 1.19 kg, respectively. A force of constant magnitude F acts on the rod at the end opposite the rotation axis. The direction of the force is perpendicular to both the rod's length and the rotation axis. Calculate the value of F that will accelerate the rod from rest to an angular speed of 6.45 rad/s in 8.49 s. F = 23.15

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Chapter1: Units, Trigonometry. And Vectors
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A uniform rod is set up so that it can rotate about an axis at perpendicular to one of its ends. The length and mass of the rod are
0.769 m and 1.19 kg, respectively. A force of constant magnitude F acts on the rod at the end opposite the rotation axis. The
direction of the force is perpendicular to both the rod's length and the rotation axis.
Calculate the value of F that will accelerate the rod from rest to an angular speed of 6.45 rad/s in 8.49 s.
N
F =
23.15
Transcribed Image Text:A uniform rod is set up so that it can rotate about an axis at perpendicular to one of its ends. The length and mass of the rod are 0.769 m and 1.19 kg, respectively. A force of constant magnitude F acts on the rod at the end opposite the rotation axis. The direction of the force is perpendicular to both the rod's length and the rotation axis. Calculate the value of F that will accelerate the rod from rest to an angular speed of 6.45 rad/s in 8.49 s. N F = 23.15
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