A tensile specimen made of hot-rolled AISI 1020 steel is loaded to point corresponding to a strain of 43%.60Su = 66 ksiStress σ (ksi)40 B20000THSy = 39 ksiSe = 36 ksiHot-rolled 1020 steelF10 20 30 4050 60 70 80 90 100 110 120 130 140 150 160Strain € (%)T1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2.0 2.1 2.2 2.3 2.4 2.5 2.6Area ratio R0.10.20.30.40.5Area reduction A,What value of strain is applicable to this location?0.6

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Answered: A tensile specimen made of hot-rolled…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A cylindrical specimen of 1018 steel having a diameter of 6.35 mm and a gauge length of 38.1 mm is pulled in tension. Use the load-elongation characteristics tabulated below. The modulus of resilience (Ur) is the area under the engineering stress-strain curve. Compute the Ur.
The stress-strain curve for a material is shown below. The modulus of toughness for this material is most closely equal to: σ (ksi) 105 90 75 60 8 45 30 15 0 0 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0 0.001 0.002 0.003 0.004 0.005 0.006 0.007 28 ksi 16 ksi 38 ksi 22 ksi € (in./in.)
Problem 2: A specimen of steel having an initial diameter of 0.503 in was tested in tension using a gauge length of 2 inches. The following data were obtained for the tension. Plot the stress strain data and determine the modulus of elasticity, and the yield strength of the material. Elastic State Load P Ibf Elongation in 1 000 0.0004 2 000 0.0006 3 000 0.0010 4 000 0.0013 7 000 0.0023 8 400 0.0028 8 800 0.0036 9 200 0.0089
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the material had a tensile stress of 67.7 ksi then was unloaded. the original length of the specimen was 5.0 inches. show the line on the diagram you would expect the material to follow as the load was released. estimate the length of the specimen after all load was removed.
1. A tension test on an aluminum plate resulted in the following engineering stress-engineering strain data as reported in the first and second column of the table below (reduction of area, RA=17%): S (psi) e (in/in) σ (psi) ε (in/in) 10500 0.001 10510.5 0.000995 21000 0.002 31200 0.003 41300 0.004 51200 0.005 61200 0.006 70600 0.007 74700 0.0075 76800 0.008 77600 0.0085 78000 0.009 78400 0.0095 78700 0.01 81200 0.02 83000 0.03 84200 0.04 85400 0.05 86200 0.06 86800 0.07 *87200 0.08 **86200 0.1 Note: * maximum load, ** load at fracture a) Calculate the corresponding true stress and true strain and give your results in a table along with the engineering stress, engineering strain shown in the of table above (column 3 and 4). b) Plot the true stress-true strain curve on a rectangular coordinate. c) Plot the true stress-true strain curve on a log-log graph and determine the plastic flow curve parameters K and n, the yield strength, Y, and the elastic modulus, E of the material.
2) The stress-strain diagram for an alloy specimen having an original diameter of 0.5 in. and a gage length of 2 in. is shown in the figure below. TENSILE STRESS (MPA) 450 400 350 300 250 200 150 100 50 Part A 0 0 STRESS VS. STRAIN 0.002 0.004 STRAIN 0.006 Determine the modulus of resilience. Show units. Part B Determine the modulus of elasticity of the material. Part C Estimate the Yield Strength of the material. 0.008 0.01
I am asking because it is a hard question
a. Plot the stress strain diagram b. Find the modulus of elasticity, ultimate stress and fracture stress and explain each term. Define modulus of toughness and find the same for the above specimen. Load (kN) Elongation (mm) 11.1 31.9 0.0175 0.0600 37.8 0.1020 40.9 0.1650 43.6 53.4 62.3 64.5 0.2490 1.0160 3.0480 6.3500
A high-impulse universal testing machine is being used to determine the Young's Modulus of a rectangular solid specimen (l = 20 cm, t = 1.5 cm, w = 2 cm). The machine produces 35,000 Ns that causes the impact force of compression resulted to a 1 mm deformation in the length of the specimen in 0.05 s. Determine the Young's modulus of the specimen expressed in MPa. Round off your answer to the nearest whole number
400 350 300 250 200 150 100 50 0.002 0.004 0.006 0.008 0.01 Strain Stress (MPa)
The following data was obtained as a result of tensile testing of a standard 0.505 inch diameter test specimen of magnesium. After fracture, the gage length is 2.245 inch and the diameter is 0.466 inch. a). Calculate the engineering stress and strain values to fill in the blank boxes and plot the data. Load(lb) Gage Length (in) Stress (kpsi) Strain 0 2 1000 2.00154 2000 2.00308 3000 2.00462 4000 2.00615 5000 2.00769 5500 2.014 6000 2.05 6200 (max) 2.13 6000 (fracture) 2.255 b). Calculate the modulus of elasticity c). If another identical sample of the same material is pulled only to 6000 pounds and is unloaded from there, determine the gage length of the sample after unloading.

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