A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station's 11 p.m. news is found for each sample. The results are given in the table below. Age Group 55 or Older Watch 11 p.m. News? Yes 18 or less 19 to 35 36 to 54 59 191 49 201 61 189 84 166 Total 253 747 No Total 250 250 250 250 1,000

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### Chi-Square Test for Independence

To determine if the proportions \( p_1, p_2, p_3, \) and \( p_4 \) are equal, we use a chi-square test for independence. Perform this test by setting the significance level \( \alpha = 0.05 \).

**Chi-Square Test Statistic:**
\[ \chi^2 = 13.900 \]

Decision Rule:
- If the chi-square test statistic is greater than the critical value, reject the null hypothesis \( H_0 \).

Result:
- **Decision:** Reject \( H_0 \): independence

### Confidence Interval Calculation

**Task:**
Compute a 95% confidence interval for the difference between \( p_1 \) and \( p_4 \). Round your answers to three decimal places. Indicate negative amounts with a minus sign.

**95% Confidence Interval:**
\[ ( \text{Lower bound}, \text{Upper bound} ) \]

(Note: The actual interval values are to be computed by the user as per the instructions and aren't provided in the image.)
Transcribed Image Text:### Chi-Square Test for Independence To determine if the proportions \( p_1, p_2, p_3, \) and \( p_4 \) are equal, we use a chi-square test for independence. Perform this test by setting the significance level \( \alpha = 0.05 \). **Chi-Square Test Statistic:** \[ \chi^2 = 13.900 \] Decision Rule: - If the chi-square test statistic is greater than the critical value, reject the null hypothesis \( H_0 \). Result: - **Decision:** Reject \( H_0 \): independence ### Confidence Interval Calculation **Task:** Compute a 95% confidence interval for the difference between \( p_1 \) and \( p_4 \). Round your answers to three decimal places. Indicate negative amounts with a minus sign. **95% Confidence Interval:** \[ ( \text{Lower bound}, \text{Upper bound} ) \] (Note: The actual interval values are to be computed by the user as per the instructions and aren't provided in the image.)
### Study of Viewer Age and 11 p.m. News Viewership

A television station is conducting a study to explore the relationship between viewership of its 11 p.m. news program and viewer age. Age groups are categorized as follows: 18 years or less, 19 to 35, 36 to 54, and 55 or older. A random sample of 250 television viewers in each age group was selected, and their viewership of the 11 p.m. news was recorded. The findings are displayed in the table below:

| Watch 11 p.m. News? | 18 or less | 19 to 35 | 36 to 54 | 55 or Older | Total |
|---------------------|------------|----------|----------|-------------|-------|
| Yes                 | 49         | 59       | 61       | 84          | 253   |
| No                  | 201        | 191      | 189      | 166         | 747   |
| Total               | 250        | 250      | 250      | 250         | 1,000 |

#### Hypothesis Testing

- **Objective:** Test the null hypothesis \( H_0 \) that the proportions of viewers in each age group who watch the station's 11 p.m. news (\( p_1, p_2, p_3, p_4 \)) are equal, implying that viewership is independent of age group.

- **Method:** Perform a chi-square test for independence with a significance level \( \alpha = 0.05 \).

- **Chi-Square Calculation:**  
  \[
  \chi^2 = 13.900
  \]

### Conclusion

- **Decision:** Reject \( H_0 \) indicating dependence between viewer age group and viewership of the 11 p.m. news program.

This analysis suggests that there is a statistically significant relationship between the age group of viewers and their likelihood of watching the 11 p.m. news, implying that factors related to age may influence viewership patterns.
Transcribed Image Text:### Study of Viewer Age and 11 p.m. News Viewership A television station is conducting a study to explore the relationship between viewership of its 11 p.m. news program and viewer age. Age groups are categorized as follows: 18 years or less, 19 to 35, 36 to 54, and 55 or older. A random sample of 250 television viewers in each age group was selected, and their viewership of the 11 p.m. news was recorded. The findings are displayed in the table below: | Watch 11 p.m. News? | 18 or less | 19 to 35 | 36 to 54 | 55 or Older | Total | |---------------------|------------|----------|----------|-------------|-------| | Yes | 49 | 59 | 61 | 84 | 253 | | No | 201 | 191 | 189 | 166 | 747 | | Total | 250 | 250 | 250 | 250 | 1,000 | #### Hypothesis Testing - **Objective:** Test the null hypothesis \( H_0 \) that the proportions of viewers in each age group who watch the station's 11 p.m. news (\( p_1, p_2, p_3, p_4 \)) are equal, implying that viewership is independent of age group. - **Method:** Perform a chi-square test for independence with a significance level \( \alpha = 0.05 \). - **Chi-Square Calculation:** \[ \chi^2 = 13.900 \] ### Conclusion - **Decision:** Reject \( H_0 \) indicating dependence between viewer age group and viewership of the 11 p.m. news program. This analysis suggests that there is a statistically significant relationship between the age group of viewers and their likelihood of watching the 11 p.m. news, implying that factors related to age may influence viewership patterns.
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