A student carried out a lens experiment to investigate the magnification of an image. The apparatus is shown in Fig. 5.1. V illuminated lens screen object Fig. 5.1 The object is a triangular hole in a screen. Fig. 5.2 shows this, actual size. 1.5cm 2.0 cm Fig. 5.2 The student set the distance u at 35.0 cm and moved the screen to obtain a sharply focused image. The image distance v was 72.3 cm. (a) (1) Calculate m, the magnification, using the equation M vlu.

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Chapter1: Units, Trigonometry. And Vectors
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A student carried out a lens experiment to investigate the magnification of an image. The
apparatus is shown in Fig. 5.1.
illuminated
lens
screen
object
Fig. 5.1
The object is a triangular hole in a screen. Fig. 5.2 shows this, actual size.
1.5cm
2.0 cm
Flg. 5.2
The student set the distance u at 35.0 cm and moved the screen to obtain a sharply focused
image. The image distance v was 72.3 cm.
(a) (1) Calculate m, the magnification, using the equation
m= vlu.
MR
Transcribed Image Text:A student carried out a lens experiment to investigate the magnification of an image. The apparatus is shown in Fig. 5.1. illuminated lens screen object Fig. 5.1 The object is a triangular hole in a screen. Fig. 5.2 shows this, actual size. 1.5cm 2.0 cm Flg. 5.2 The student set the distance u at 35.0 cm and moved the screen to obtain a sharply focused image. The image distance v was 72.3 cm. (a) (1) Calculate m, the magnification, using the equation m= vlu. MR
(11) Draw a diagram of the image, actual size, for a magnification m = 2.0.
(b) The image distance v is the distance from the screen to the centre of the lens.
Explain briefly how you would position a metre rule to obtain an accurate value for v.
You may drawa diagram.
Transcribed Image Text:(11) Draw a diagram of the image, actual size, for a magnification m = 2.0. (b) The image distance v is the distance from the screen to the centre of the lens. Explain briefly how you would position a metre rule to obtain an accurate value for v. You may drawa diagram.
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