Question 5Which of these diagrams is correct?Not yetansweredobjectimageMarked out of 5FlagquestionAlensobjectBimageflensobjectimageflensSelect one:a. Аb. BC. CQuestion 6Which of these ray diagrams is correct?

Properties of a convex lens:(a) When a ray parallel to the principal axis falls on the convex lens,…

Answered: Question 5 Which of these diagrams is…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A lens produces an upright virtual image between the lens and the focal length of the lens, on the same side of the lens as where the object is located, when the object is outside the focal length of the lens. The focal length of the lens is 15cm and the image is 0.3 times the size of the object. a) Determine the type of lens. b) Determine the distance of the object from the lens. c) Determine the distance of the image from the lens
Which of the following is not a problem for refracting telescopes? O A. Different wavelengths of light are focused at slightly different locations. O B. The quality of the glass lens in transparency and in the shape of both surfaces must be high. C. The secondary mirror blocks some of the light passing through the primary lens. D. The primary lens can only be supported at the edges making deformation of large lenses difficult to avoid.
IP An object is located to the left of a concave lens whose focal length is -41 cm . The magnification produced by the lens is mị = 0.32. Part A To decrease the magnification to m2 = 0.23, should the object be moved closer to the lens or farther away? closer farther away Submit Request Answer Part B Calculate the distance through which the object should be moved. Express your answer using two significant figures. ΑΣφ Ad, = cm Submit Request Answer Provide Feedback |0
4. Diverging Lens - Object Inside Focal Point An object with heigh 0.75cm is placed a distance of 2.5 cm in front of a thin diverging lens with focal length -15cm. A. What is the image position in cm? Please draw a ray diagram and use the lens equation to solve algebraically. B. What is the image height? C. What is the magnification? ↑ 1 1 do d₁ + = 1 m= hi ho di do Skill: Find an Image Using 3 Principle Rays in Ray Diagram Skill: Find an Image Using the Lens Equation
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A = 60 B = 70 C = 170 D = 7
8 a) The diagram shows two light rays that form an intermediate image by the objective lens an optical compound microscope. These rays are incident on the eyepiece lens. The focal points of the two lenses are marked. not to eyepiece lens scale objective lens to Draw rays on the diagram to show the formation of the final image. b) The object is viewed when the microscope is in normal adjustment. State what is meant by normal adjustment when applied to a compound microscope. c) The object O is placed at a distance of 24.0 mm from the objective lens and the final image is formed at a distance 240 mm from the eyepiece lens. The focal length of the objective lens is 20.0 mm and that of the eyepiece lens is 60.0 mm. The near point of the observer is at a distance of 240 mm from the eyepiece lens. Calculate the distance between the lenses.
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2. Spherical (Curved) Mirrors - Concave Mirror An object is placed at a distance of 15cm in front of a concave mirror whose focal length if 10.5 cm. A. What is the image distance? Please draw a Ray Diagram AND Use the Mirror Equation to Find the Image. B. What is the magnification? ). 1 1 + do di 1 ƒ f = R Skill: Use 3 Principal Rays to Draw a Ray Diagram and Find the Image m= h₁ ho Skill: Use the Mirror Equation to Algebraically Solved for Image Distance, then Solve for Magnification d₁ do

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Question 5 Which of these diagrams is correct? Not yet answered object image Marked out of 5 Flag question A lens object B image f lens object image f lens Select one: a. А b. B C. C Question 6 Which of these ray diagrams is correct?