the only parts that i need help with is parts g and h + Understanding LensesLearning Goal:To learn the quantitative use of the lens equation, as well as how to determine qualitativeproperties of solutions.In working with lenses, there are three important quantities to consider: The object distance8 is the distance along the axis of the lens to the object. The image distance is thedistance along the axis of the lens to the image. The focal length f is an intrinsic propertyof the lens. These three quantities are related through the equation= + = = =Note that this equation is valid only for thin, spherical lenses. Unless otherwise specified, alens problem always assumes that you are using thin, spherical lenses.The equation above allows you to calculate the locations of images and objects. Frequently.you will also be interested in the size of the image or object, particularly if you areconsidering a magnifying glass or microscope. The ratio of the size of an image to the sizeof the object is called the magnification. It is given by=//mwhere y' is the height of the image and y is the height of the object. The second equalityallows you to find the size of the image (or object) with the information provided by the thinlens equation.All of the quantities in the above equations can take both positive and negative values.Positive distances correspond to real images or objects, while negative distancescorrespond to virtual images or objects. Positive heights correspond to upright images orobjects, while negative heights correspond to inverted images or objects. The followingtable summarizes these properties:positive negativevirtual8 realrealy uprighty uprightvirtualinvertedinvertedThe focal length f can also be positive or negative. A positive focal length corresponds to aconverging lens, while a negative focal length corresponds to a diverging lens.▾Consider an object with 8 = 12 cm that produces an image with = 15 cm. Note that whenever you are working with a physical object, the object distance will be positive (in multiple optics setups, you will encounter"objects" that are actually images, but that is not a possibility in this problem). A positive image distance means that the image is formed on the side of the lens from which the light emerges.Part AFind the focal length of the lens that produces the image described in the problem introduction using the thin lens equation.Express your answer in centimeters, as a fraction or to three significant figures.f = 8.67 cm.▼Submit▾ Part B✓ CorrectConsidering the sign of f, is the lens converging or diverging?convergingOdivergingSubmitPrevious Answers▾ Part C✓ CorrectSubmitPrevious AnswereWhat is the magnification m of the lens?Express your answer as a fraction or to three significant figures.7 -1.25Part DPrevious Answers✔Correct< 10 of 22Review | Constants Learning Goal:To learn the quantitative use of the lens equation, as well as how to determine qualitativeproperties of solutions.In working with lenses, there are three important quantities to consider. The object distances is the distance along the axis of the lens to the object. The image distance s' is thedistance along the axis of the lens to the image. The focal length f is an intrinsic propertyof the lens. These three quantities are related through the equation+=+=+Note that this equation is valid only for thin, spherical lenses. Unless otherwise specified, alens problem always assumes that you are using thin, spherical lenses.mThe equation above allows you to calculate the locations of images and objects. Frequently.you will also be interested in the size of the image or object, particularly if you areconsidering a magnifying glass or microscope. The ratio of the size of an image to the sizeof the object is called the magnification. It is given byVwhere y' is the height of the image and y is the height of the object. The second equalityallows you to find the size of the image (or object) with the information provided by the thinlens equation.=}All of the quantities in the above equations can take both positive and negative values.Positive distances correspond to real images or objects, while negative distancescorrespond to virtual images or objects. Positive heights correspond to upright images orobjects, while negative heights correspond to inverted images or objects. The followingtable summarizes these properties:8 reapositive negativevirtualvirtualrealy uprighty uprightinvertedinvertedThe focal length f can also be positive or negative. A positive focal length corresponds to aconverging lens, while a negative focal length corresponds to a diverging lens.Part FWhat is the object distance? You will need to use the magnification equation to find a relationship between s and s'. Then substitute into the thin lens equation to solve for 8.Express your answer in centimeters, as a fraction or to three significant figures.8 = 12.0 cmSubmitAll attempts used; correct answer displayedPart GWhat is the image distance?Express your answer in centimeters, as a fraction or to three significant figures.SubmitPrevious Answerefor Part for Part Ado for Part&redo fort Gresor Part G keyboard shortcuts for Part G help for Part Ga vonPart HX Incorrect; Try Again; 5 attempts remaining=1512Previous Answers Request AnswerA lens placed at the origin with its axis pointing along the x axis produces a real inverted image at z = -24 cm that is twice as tall as the object.What is the image distance?Express your answer in centimeters, as a fraction or to three significant figures.Submitor Part Hfor avec1512do for Part redo forart H restor Part H keyboard shortcuts for Part H help for Part HcmPrevious Anawara Requent Anawarcm

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Answered: a ndly. ✓ in o a Part G What is the…

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...