1.) You put a lens in front of phone screen and the light coming through the lens makes a large version of the image on your screen appear on the wall on the opposite side of the lens from your phone. In the above example the lens shown is (convex or concave) and (converging or diverging) The image formed will be (virtual, real)  and (invert or upright)

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Chapter1: Units, Trigonometry. And Vectors
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1.) You put a lens in front of phone screen and the light coming through the lens makes a large version of the image on your screen appear on the wall on the opposite side of the lens from your phone.

In the above example the lens shown is (convex or concave) and (converging or diverging)

The image formed will be (virtual, real)  and (invert or upright)

 

 

2.) Choose the equation or equations that you will need to use to find the object distance and magnification.

Select one or more:
a. Mirror or Thin Lens Equation: 1/do + 1/di =1/f,  ho/hi = -do/di
b. Induced emf of a coil:  ε = -NΔΦ/Δt
c. Magnetic Flux: Φ = BAcosθ
d. Doppler shift:  ƒl = ƒ(1 ± u/c)
e. B Field at the center of a loop: B = Nµ0L/2R
f. Index of refraction n = c/v
g. Magnetic Force on a moving charge: F = qvBsinθ
h. B-field of a long straight wire: B = μ0I/2πR
i. c = fλ
j. Torque on a loop:  τ = NIABsinθ
k. Force on a current carrying wire: F = BILsinθ
l. Force between current carrying wires separated by distance d: F = µ0I1I2L/2πd
m. Force on an object mass m moving in a circle of radius R: F = mv2/R
n. Snell’s law: n1sinθ1 = n2sinθ2
You put a lens in front of phone screen and the light coming through the lens makes a large version of the image on
your screen appear on the wall on the opposite side of the lens from your phone.
The focal length of the lens is 8.8 cm. If the lens is 200 cm from the image on the wall, what is distance in cm from
the lens to your phone screen? keep two digits past the decimal point.
Answer:
You put a lens in front of phone screen and the light coming through the lens makes a large version of the image on
your screen appear on the wall on the opposite side of the lens from your phone.
If the lens is 200 cm from the image on the wall, and your phone was 10 cm on the other side of the lens how many
times bigger would the image on the wall be compared to the size on your phone screen?
Answer:
Transcribed Image Text:You put a lens in front of phone screen and the light coming through the lens makes a large version of the image on your screen appear on the wall on the opposite side of the lens from your phone. The focal length of the lens is 8.8 cm. If the lens is 200 cm from the image on the wall, what is distance in cm from the lens to your phone screen? keep two digits past the decimal point. Answer: You put a lens in front of phone screen and the light coming through the lens makes a large version of the image on your screen appear on the wall on the opposite side of the lens from your phone. If the lens is 200 cm from the image on the wall, and your phone was 10 cm on the other side of the lens how many times bigger would the image on the wall be compared to the size on your phone screen? Answer:
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