A straight conductor is moving with a velocity of 3 m/s at right angles to a magnetic field of induction equal to 4.5 × 10 Wb/m. If an e.m.f. developed between its ends is 1.35 x 10 volts. What must be its length ?
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A: Given: w =1.8 cm =1.8*10-2 mt = 1.0 mm =1.0 *10-3 mB=1.2 TI=15 A∆V=1.02 μV=1.02*10-6 V
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A: Given The acceleration of the conductor is a=0.1 m/s2. The initial emf of the conductor is e1=0 V.…
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A: Given Magnetic Field B =0.120 T Velocity v = 4.50 x 106 m/s Distance D = 1.00 cm = 1.00 x 10-2 m
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A: Using Faraday's law of electromagnetic induction Where e = emf induced, t = time, = Magnetic flux
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A: Given value--- No. of turns = 69. Area = 20 cm2. Resistance = 5 Ohm. Magnetic field = 3 × 10-2 T.…
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A: Length of the wire, L=20km=20×103m Orbital speed, v=7.86×103m/s Magnetic field, B=1.51×10-5T
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A: Charge (q) = 5.47 C Speed (v) = 6.98 m/s Magnetic field (B) = 6.28 T
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Q: A V = 30 mV battery is connected to a single turn loop of dimensions a = 13 cm by b = 12.5 cm has a…
A: The given values are, V=30 mV=0.030 VA=a×b=13 cm×12.5 cm=13×10-2 m×12.5×10-2 m=162.5×10-4 m2R=15.5…
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A: Proper solution is provided given below:Explanation:Step 1: Finding current The current can be…
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Q: solenoid of 35 turns and area 20 cm2 has its ends connected together though a resistance of 5 Ohms.…
A: Given number of turns N = 35 area A = 20 cm2 = 20 × 10-4 m2 resistance R = 5 ohm magnetic flux…
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A: Magnetic field.
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Q: Consider a straight conductor of length 6.3 cm. The conductor moves at right angles to a magnetic…
A: length of conductor,l=6.3 cm=6.3 x 10-2 mmagnetic field strength, B=10-3 Te.m.f. = 2.5 x 10-5…
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A: Our question is to find the rate dBdt at which the magnetic field through the loop be changing.
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- A straight conductor of length / moves with an acceleration a = 0.1 ms2 at the right angle to the magnetic field of uniform strength B =11.9 T. Calculate 7, considering that the e.m.f., e = Blu, between the ends of the conductor increased from 0 to 5 V during the first 20 s after the beginning of motion. Answer: m ◆A charge moves out of a radiation source with the velocity to the left. Once it enters a uniform magnetic field B it moves upward. What is the type of chargeSuppose that an ion source in a mass spectrometer produces doubly ionized gold ions (Au2+), each with a mass of 3.27 × 10-25 kg. The ions are accelerated from rest through a potential difference of 1.70 kV. Then, a 0.510-T magnetic field causes the ions to follow a circular path. Determine the radius of the path.
- Consider a straight conductor of length 9.7 cm. The conductor moves at right angles to a magnetic field of uniform strength B = 10-3 T generating e.m.f. of 2.5 × 10-³ V. Calculate the velocity of the straight conductor. Give your answer in SI units. Answer: Choose... +A 1450 turn coil of wire, 6.16 cm in diameter, is in a magnetic field that drops from 0.723 T to 0 T in 41.9 ms. The axis of the coil is parallel to the field. What is the emf (in V) of the coil?Crossed electric and magnetic fields have magnitudes of 4.65 V/m and 74.5 mT. Find the speed at which electrons moving perpendicular to both fields can travel through them without being deflected?
- ASAPA circular conducting loop with a radius of 1.00 m and a small gap filled with a 10.0 resistor is oriented in the xy-pane. If a magnetic field of 2.0 T, making an angle of 30° with the z-axis increases to 9.0 T, in 2.0 s, what is the magnitude of the current that will be caused to flow in the conductor?MYMIVIVH uns w pui SIVIN IN WEHE saw piwa ISMIMIN 29. An electron is travelling at 100 km/s parallel to a long straight horizontal conductor a distance of 3.00 cm from the conductor. A current of 12.0 A runs through the wire as the electron travels parallel to it, in the same direction as the electron's velocity. Find the strength of the external electric field that will prevent the elec- tron from deviating from its original path. Express your answer in V/m.