A circular conducting loop with a radius of 1.00 m and a small gap filled with a 10.0 resistor is oriented in the xy-pane. If a magnetic field of 2.0 T, making an angle of 30° with the z-axis increases to 9.0 T, in 2.0 s, what is the magnitude of the current that will be caused to flow in the conductor?
A circular conducting loop with a radius of 1.00 m and a small gap filled with a 10.0 resistor is oriented in the xy-pane. If a magnetic field of 2.0 T, making an angle of 30° with the z-axis increases to 9.0 T, in 2.0 s, what is the magnitude of the current that will be caused to flow in the conductor?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
![**Problem Statement**
A circular conducting loop with a radius of 1.00 m and a small gap filled with a 10.0 Ω resistor is oriented in the xy-plane. If a magnetic field of 2.0 T, making an angle of 30° with the z-axis increases to 9.0 T, in 2.0 s, what is the magnitude of the current that will be caused to flow in the conductor?
**Analysis**
This problem involves electromagnetic induction, where a changing magnetic field induces an electromotive force (EMF) in a conducting loop. This induced EMF will create a current, which flows through the resistor in the loop.
**Solution**
To solve this, use Faraday’s Law of Induction, which states that the induced EMF in a loop is equal to the negative rate of change of magnetic flux through the loop. The formula can be expressed as:
\[ \text{EMF} = -\frac{\Delta \Phi}{\Delta t} \]
where \(\Delta \Phi\) is the change in magnetic flux and \(\Delta t\) is the change in time.
Next, calculate the magnetic flux (\(\Phi\)), given by:
\[ \Phi = B \cdot A \cdot \cos(\theta) \]
where:
- \(B\) is the magnetic field strength,
- \(A\) is the area of the loop (\(A = \pi r^2\), with \(r\) being the radius of the loop),
- \(\theta\) is the angle between the magnetic field and the normal to the loop.
**Step-by-step Calculations:**
1. Calculate the area of the loop:
\[ A = \pi (1.00 \, \text{m})^2 = \pi \, \text{m}^2 \]
2. Determine the initial and final magnetic flux:
\[ \Phi_{\text{initial}} = 2.0 \, \text{T} \cdot \pi \, \text{m}^2 \cdot \cos(30^\circ) \]
\[ \Phi_{\text{final}} = 9.0 \, \text{T} \cdot \pi \, \text{m}^2 \cdot \cos(30^\circ) \]
3. Calculate the change in magnetic flux](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F93d9f4fa-0622-4417-979d-12a19703a696%2Ff1767381-03ee-405a-a7f7-a9c53fd5677d%2Fzvsudn6_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement**
A circular conducting loop with a radius of 1.00 m and a small gap filled with a 10.0 Ω resistor is oriented in the xy-plane. If a magnetic field of 2.0 T, making an angle of 30° with the z-axis increases to 9.0 T, in 2.0 s, what is the magnitude of the current that will be caused to flow in the conductor?
**Analysis**
This problem involves electromagnetic induction, where a changing magnetic field induces an electromotive force (EMF) in a conducting loop. This induced EMF will create a current, which flows through the resistor in the loop.
**Solution**
To solve this, use Faraday’s Law of Induction, which states that the induced EMF in a loop is equal to the negative rate of change of magnetic flux through the loop. The formula can be expressed as:
\[ \text{EMF} = -\frac{\Delta \Phi}{\Delta t} \]
where \(\Delta \Phi\) is the change in magnetic flux and \(\Delta t\) is the change in time.
Next, calculate the magnetic flux (\(\Phi\)), given by:
\[ \Phi = B \cdot A \cdot \cos(\theta) \]
where:
- \(B\) is the magnetic field strength,
- \(A\) is the area of the loop (\(A = \pi r^2\), with \(r\) being the radius of the loop),
- \(\theta\) is the angle between the magnetic field and the normal to the loop.
**Step-by-step Calculations:**
1. Calculate the area of the loop:
\[ A = \pi (1.00 \, \text{m})^2 = \pi \, \text{m}^2 \]
2. Determine the initial and final magnetic flux:
\[ \Phi_{\text{initial}} = 2.0 \, \text{T} \cdot \pi \, \text{m}^2 \cdot \cos(30^\circ) \]
\[ \Phi_{\text{final}} = 9.0 \, \text{T} \cdot \pi \, \text{m}^2 \cdot \cos(30^\circ) \]
3. Calculate the change in magnetic flux
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you

College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning

University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press

College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning

University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press

Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning

Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley

College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON