Tutorial ExerciseIn an experiment designed to measure the Earth's magnetic field using the Hall effect, a copper bar 0.415 cmthick is positioned along an east-west direction. Assume n = 8.46 x 1028 electrons/m3 and the plane of thebar is rotated to be perpendicular to the direction of B. If a current of 8.00 A in the conductor results in a Hallvoltage of 5.52 x 10-12 v, what is the magnitude of the Earth's magnetic field at this location?

Given that thickness t = 0.415 cm current = 8 A hall voltage = 5.52…

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Consider two protons trapped on the same geomagnetic field line. One proton has kinetic energy 10 eV and the other has kinetic energy of 10 keV. Which statement about the magnetic field strength at their respective mirror points is correct? A. B10 eV < B10 keV B. B10 eV > B10 keV C. B10 eV = B10 keV D. Not enough information is given
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Need IV & V Use the following constants if necessary. Coulomb constant, k = 8.987×10^9 N⋅m^2/C^2 . Vacuum permitivity, ϵ0= 8.854×10^−12 F/m. Magnetic Permeability of vacuum, μ0 = 12.566370614356×10^−7 H/m. Magnitude of the Charge of one electron, e = −1.60217662×10^−19 C. Mass of one electron, m_e = 9.10938356×10^−31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, μC means microcoulomb .
A particle with charge 2.50 µC and mass 3.00x10-11 kg is initially traveling in the +y-direction with a speed vo = 1.60x105 m/s. It then enters a region containing a uniform magnetic field that is directed into, and perpendicular to, the page in the figure (Figure 1). The magnitude of the field is 0.450 T. The region extends a distance of 25.0 cm along the initial direction of travel; 75.0 cm from the point of entry into the magnetic field region is a wall. The length of the field- free region is thus 50.0 cm. When the charged particle enters the magnetic field, it follows a curved path whose radius of curvature is R. It then leaves the magnetic field after a time t1, having been deflected a distance Az1. The particle then travels in the field-free region and strikes the wall after undergoing a total deflection Ar. Part C Determine Az1, the horizontal deflection at the point of exit from the field. Express your answer in meters. Π ΑΣφ. ? Ar1 = Submit Previous Answers Request Answer…
T electrical force between two uranium nuclei placed a distance of 1.81 x 10^-12 m apart from one another? 0.952 N 0.298 N 0.595 N 0.833 N So here goes What is the magnitude of the
Use the following constants if necessary. Coulomb constant, k=8.987×109N⋅m2/C2. Vacuum permitivity, ϵ0=8.854×10−12F/m. Magnetic Permeability of vacuum, μ0=12.566370614356×10−7H/m. Magnitude of the Charge of one electron, e=−1.60217662×10−19C. Mass of one electron, me=9.10938356×10−31kg. Unless specified otherwise, each symbol carries their usual meaning. For example, μC means microcoulomb . You have an infinite wire with linear charge density λ=5C/m. The wire is placed along z-axis. Find the magnitude of Electric Field at a distance 21cm perpendicular away from the wire. Magnitude of Electric Field
In an experiment designed to measure the Earth's magnetic field using the Hall effect, a copper bar 0.560 cm thick is positioned along an east–west direction. Assume n = 8.46 × 1028 electrons/m3 and the plane of the bar is rotated to be perpendicular to the direction of B. If a current of 8.00 A in the conductor results in a Hall voltage of 4.30 10-12 V, what is the magnitude of the Earth's magnetic field at this location?
No magnetic poles have ever been seen in nature, but we can assume that they exist and generalize Maxwell's equations accordingly. The generalized Maxwell equations in this case (in Gaussian units) will be as follows: V.Ē = 47Pe V.B = 4TPm 1 0B 4 Jm V xE = с де V ×B = c ôt -Je In the above expressions, pm is the magnetic charge density and jm is the magnetic current density. For simplicity, we denote the set of electrical and magnetic quantities by e and M. in other words M = (B, Jm; Pm, ...) , E = (E, Je, Pe, ...)
A 0.68 T magnetic field is applied to a paramagnetic gas whose atoms have an intrinsic magnetic dipole moment of 1.3 x 1024 J/T. At what temperature will the mean kinetic energy of translation of the atoms equal the energy required to reverse such a dipole end to end in this magnetic field? Number i Units
a-Gbogle Chrome quiz/attempt.php?attempt=186776&cmid=3903&page=1 Physics II (CRN: 50010) A particle with charge g= 1.2 C and a long wire carrying current I= 3 A is on the ry-plane at the moment the charge is at point Pat distance d= 0.3 cm from the wire and has velocity v = 1.7 m/s in the r-direction. What is the magnitude of the magnetic force acting on the charge in units of nanonewtons? (Ho = 4x x 10 7T - m/A) Answer Next ge
Use the following constants if necessary. Coulomb constant, k=8.987×109N⋅m2/C2. Vacuum permitivity, ϵ0=8.854×10−12F/m. Magnetic Permeability of vacuum, μ0=12.566370614356×10−7H/m. Magnitude of the Charge of one electron, e=−1.60217662×10−19C. Mass of one electron, me=9.10938356×10−31kg. Unless specified otherwise, each symbol carries their usual meaning. For example, μC means microcoulomb A current carrying wire(wire-1) with i1=14Amperes is placed at the origin on the Y-Z plane. Another current carrying wire(wire-2) with i2=14Amperes is placed l=11m distance apart on the Y-axis. The point P2 is l1=8m from the wire-1. P1(0,8,−13), P2(0,8,0) and the point P3(0,8,10) are on the same line. The direction of the current is given in the figure. Step 1: Consider a wire-1 only. a)Calculate magnetic field at P1 x component, y component & z component Calculate the magnetic field at P2 x component, y component & z component Step 2:Consider both wires b)Now what is the net magnetic…

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