We want to use the Earth's magnetic field to apply a torque on a current loop. Suppose the Earth's magnetic field at this location is 5*10^(-5) Tesla (0.5 Gauss) and we want to apply a maximum of 1.2 Newton-meters of torque (if the loop is oriented parallel to the magnetic field). The loop is circular with a radius of 1.4. How much current do we need to apply to the loop? Amps The loop is made of aluminum wire (circular in cross section) with a thickness of 0.02 meters (or a radius of 0.01 meters). Aluminum has a resistivity of 2.65*10^(-8) Ohm meters. How much power does it take to power the loop? Watts
We want to use the Earth's magnetic field to apply a torque on a current loop. Suppose the Earth's magnetic field at this location is 5*10^(-5) Tesla (0.5 Gauss) and we want to apply a maximum of 1.2 Newton-meters of torque (if the loop is oriented parallel to the magnetic field). The loop is circular with a radius of 1.4. How much current do we need to apply to the loop? Amps The loop is made of aluminum wire (circular in cross section) with a thickness of 0.02 meters (or a radius of 0.01 meters). Aluminum has a resistivity of 2.65*10^(-8) Ohm meters. How much power does it take to power the loop? Watts
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Transcribed Image Text:We want to use the Earth's magnetic field to apply a torque on a current loop. Suppose the Earth's magnetic field at this location is 5*10^(-5) Tesla (0.5 Gauss) and we want to apply a
maximum of 1.2 Newton-meters of torque (if the loop is oriented parallel to the magnetic field). The loop is circular with a radius of 1.4. How much current do we need to apply to the
loop?
Amps
The loop is made of aluminum wire (circular in cross section) with a thickness of 0.02 meters (or a radius of 0.01 meters). Aluminum has a resistivity of 2.65*10^(-8) Ohm meters. How
much power does it take to power the loop?
Watts
Expert Solution
Introduction:
We are given a circular coil of known radius. We are also given the torque acting on it when kept in earth's magnetic field. We have to find the current to be passed through loop. We then find the power of loop by first finding resistance.
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