A steel component is subjected to alternate cyclical loading. The steel follows Basquin's law for high cycle fatigue, o, x Nº = C, (where the stress amplitude is in MPa). Ignore the geometric detail and assume that Marin's modifying factors are all equal to 1. You are given the minimum stress amin = -213 MPa, the maximum stress omax = 213 MPa. The material data are Tensile strength oUTS = 539 MPa, Basquin's constant c, = 875 MPa, Basquin's exponent a = 0.085. a) Calculate the stress ratio R, the stress amplitude o, in MPa and the mean stress am in MPa. The answers are acceptable with a tolerance of 0.01 for R and of 1 MPa the stresses. R: MPa MPa b) Calculate the corresponding life, in 10° cycles, (tolerance of 0.1
A steel component is subjected to alternate cyclical loading. The steel follows Basquin's law for high cycle fatigue, o, x Nº = C, (where the stress amplitude is in MPa). Ignore the geometric detail and assume that Marin's modifying factors are all equal to 1. You are given the minimum stress amin = -213 MPa, the maximum stress omax = 213 MPa. The material data are Tensile strength oUTS = 539 MPa, Basquin's constant c, = 875 MPa, Basquin's exponent a = 0.085. a) Calculate the stress ratio R, the stress amplitude o, in MPa and the mean stress am in MPa. The answers are acceptable with a tolerance of 0.01 for R and of 1 MPa the stresses. R: MPa MPa b) Calculate the corresponding life, in 10° cycles, (tolerance of 0.1
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Chapter1: Tension, Compression, And Shear
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Problem 1.6.7P: A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The...
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Do part b,c,d
![b) Calculate the corresponding life, in 10° cycles, (tolerance of 0.1
106 cycles)
N :
In practice, the load is not purely alternate, and
the minimum stress is omin =-132 MPa,
the maximum stress is omax = 294 MPa.
c) Calculate the new stress ratio R, the stress amplitude o, in MPa
and the mean stress o, in MPa.
The answers are acceptable with a tolerance of 1 MPa for
stresses.
R:
MPa
MPi
d) Calculate the corresponding life, in 10 cycles, (tolerance of 0.1
106 cycles)
N :](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10ce3489-9446-4c55-ae98-03c9ac4cb18f%2Fd8a6ecad-255b-465f-8846-fa36a8c3cedd%2F1vzy71_processed.png&w=3840&q=75)
Transcribed Image Text:b) Calculate the corresponding life, in 10° cycles, (tolerance of 0.1
106 cycles)
N :
In practice, the load is not purely alternate, and
the minimum stress is omin =-132 MPa,
the maximum stress is omax = 294 MPa.
c) Calculate the new stress ratio R, the stress amplitude o, in MPa
and the mean stress o, in MPa.
The answers are acceptable with a tolerance of 1 MPa for
stresses.
R:
MPa
MPi
d) Calculate the corresponding life, in 10 cycles, (tolerance of 0.1
106 cycles)
N :
![A steel component is subjected to alternate cyclical loading.
The steel follows Basquin's law for high cycle fatigue, o, x N = C,
(where the stress amplitude is in MPa).
Ignore the geometric detail and assume that Marin's modifying
factors are all equal to 1.
You are given
the minimum stress ain = -213 MPa,
the maximum stress omax = 213 MPa.
The material data are
Tensile strength oUTS = 539 MPa,
Basquin's constant c, = 875 MPa,
Basquin's exponent a = 0.085.
a) Calculate the stress ratio R, the stress amplitude o, in MPa and
the mean stress am in MPa.
The answers are acceptable with a tolerance of 0.01 for R and of
1 MPa the stresses.
R:
MPa
MPа
b) Calculate the corresponding life, in 10° cycles, (tolerance of 0.1
106 cycles)
N :](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10ce3489-9446-4c55-ae98-03c9ac4cb18f%2Fd8a6ecad-255b-465f-8846-fa36a8c3cedd%2Fmczi1n_processed.png&w=3840&q=75)
Transcribed Image Text:A steel component is subjected to alternate cyclical loading.
The steel follows Basquin's law for high cycle fatigue, o, x N = C,
(where the stress amplitude is in MPa).
Ignore the geometric detail and assume that Marin's modifying
factors are all equal to 1.
You are given
the minimum stress ain = -213 MPa,
the maximum stress omax = 213 MPa.
The material data are
Tensile strength oUTS = 539 MPa,
Basquin's constant c, = 875 MPa,
Basquin's exponent a = 0.085.
a) Calculate the stress ratio R, the stress amplitude o, in MPa and
the mean stress am in MPa.
The answers are acceptable with a tolerance of 0.01 for R and of
1 MPa the stresses.
R:
MPa
MPа
b) Calculate the corresponding life, in 10° cycles, (tolerance of 0.1
106 cycles)
N :
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