A steel cantilever beam, of length 2L, has an I-section, see Figure Q3. The cantilever beam is under a uniformly distributed load q = 185 kN/m applied in its vertical plane of symmetry at OA part of the span. The yield strength of the steel is [0] =360 MPa; the Young's modulus E = 240 GPa. L=1m and the coordinates of Point H are x= 0 mm, y = -60 mm, z= 0 mm.

A steel cantilever beam, of length 2L, has an I-section, see Figure Q3. The cantilever beam is under a uniformly distributed load q = 185 kN/m applied in its vertical plane of symmetry at OA part of the span. The yield strength of the steel is [0] =360 MPa; the Young's modulus E = 240 GPa. L=1m and the coordinates of Point H are x= 0 mm, y = -60 mm, z= 0 mm.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: A simple beam ABC with an overhang supports a uniform load q and a concentrated load P as shown in…

A: To Find : a) The maximum tensile stress and compressive stress. Given : The moment of inertia of…

Q: The factors of safety predicted at point H by the maximum shear stress theory of failure (Tresca…

A: For the solution refer below images.

Q: A steel beam, of lengths a=4 m and b=4 m and a hollow box cross section, is supported by a hinge…

A: Given data:A steel beam with a hollow box cross-section is given.The beam is supported by a hinge…

Q: A simply supported steel beam of length L = 16 ft is loaded with two forces PA = 350 lbf and PB =…

Q: A steel beam, of lengths a= 4 m and b=4 m and a hollow box cross section, is supported by a hinge…

A: Given:

Q: A cantilever beam of length L = 2 m supports a load P = 8.0 kN (see figure). The beam is made of…

A: The given parameters are:Load (P) = 8.0 kN = 8000 N (since 1 kN = 1000 N)Length of the beam (L) = 2…

Q: a. Deformation of the rod BD b. Normal strain in the rod BD c. Normal stress in the rod BD d. Shear…

Q: A simply supported beam hinged at A and supported at C, is carrying a distributed load and a point…

Q: Could you answer question G.

A: At point C, the value of x = a+b = 4+4 = 8 m

Q: A steel cantilever beam, of length 2L, has an I-section, see Figure Q3. The cantilever beam is under…

A: Given : The yield strength is The young modulus is The free body diagram is,

Q: A steel beam, of lengths a = 5 m and b = 2 m and a hollow box cross section, is supported by a hinge…

A: The free body diagram is-The moment equilibrium condition at point B is-

Q: a uniformly distributed load q = 290 kN/m applied in its vertical plane of symmetry at OA part of…

A: Note:- As per honor code and answering guidelines I can answer 1st three sub parts at a time.If you…

Q: A steel beam, of lengths a = 5 m and b = 5 m and a hollow box cross section, is supported by a hinge…

Q: A steel beam, of lengths a = 5 m and b = 2 m and a hollow box cross section, is supported by a hinge…

A: The free body diagram is-The moment equilibrium condition at point B is-

Q: mm and 300 mm, respectively, and the wall thickness of the cross sec = 0 kN/m to q = 4.2 kN/m for AB…

A: The free body diagram is-The moment equilibrium condition at point B is-

Q: The cross section of a beam made of thin stripsof aluminum separated by a lightweight plastic is…

A: Stress is defined as the internal resisting force per unit area. when an axial tensile load is…

Q: Bending Stress A cantilever beam of length 1.1 m carries a uniformly distributed load w, as shown in…

A: Length of the beam (L): 1 mUniformly distributed load (W): Given but not specified, please provide…

Q: (3) Draw the shear force diagram and bending moment diagram of the beam. Indicate the values of…

A: Given: The load at E, F = 5 kN The intensity of distributed load, w = 10 kN/m The elastic modulus…

Q: A cantilever beam of rectangular cross section is subjected to a concentrated load P = 150 kN acting…

Q: b) The von Mises equivalent stresses at point H can be calculated as MPa

A: The distributed load is The length is The yield stress is The elastic modulus is The dimension of…

Q: A 1000 N uniform beam at angle α = 60.0° with respect to horizontal is supported by a cable at angle…

A: Given Data: The weight of the beam is W1 = 1000 N. The weight of the mass is W2 = 1500 N. The…

Q: The beam in the figure below is subjected to a load P= 3.9 kN at its end. Young's modulus is 210 GPa…

A: P = 3.9 kNE = 210 GPa I = 5 * 106 mm4a = 1.5 mb= 1.3m

Q: A steel beam ABC carries a uniformly distributed load of w (kN/m) over the unsupported length BC, as…

Q: answer this; The factors of safety at point H predicted by the maximum-distortion-energy theory…

A: For the solution refer below images.

Q: The factors of safety at point H predicted by the maximum-distortion-energy theory (von Mises…

A: For the solution refer below images.

Q: The horizontal beam AB of 1.8-2 cross-sectional dimensions (b x h = 19 mm x 200 mm) is supported by…

Concept explainers

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.

Question

b)
The von Mises equivalent stresses at point H can be calculated as
MPa

A steel cantilever beam, of length 2L, has an I-section, see Figure Q3. The cantilever beam is under
a uniformly distributed load q = 185 kN/m applied in its vertical plane of symmetry at OA part of the
span. The yield strength of the steel is [o] = 360 MPa; the Young's modulus E = 240 GPa. L= 1 m
and the coordinates of Point H are x= 0 mm, y = -60 mm, z= 0 mm.
ty
L
q
A
L
Figure Q3
20mm
10mm H
20mm
180mm
-220mm

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given

VIEW

Step 2: Calculation of reaction force, maximum shear force and maximum moment

VIEW

Step 3: Calculation of moment of inertia, second area moment , bending stress and shear stress at H

VIEW

Step 4: Calculation of principal stresses and equivalent von mises stress

VIEW

Solution

VIEW

Step by step

Solved in 5 steps with 22 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

A steel cantilever beam, of length 2L, has an l-section, see Figure Q3. The cantilever beam is under a uniformly distributed load q = 175 kN/m applied in its vertical plane of symmetry at OA part of the span. The yield strength of the steel is [a] = 440 MPa; the Young's modulus E = 250 GPa. L=1m and the coordinates of Point H are x= 0 mm, y = -80 mm, z= 0 mm. b) O d) L q A L Deflection - Rotation - B X Figure Q3 20mm 10mm H 20mm The von Mises equivalent stresses at point H can be calculated as ул a) The factors of safety predicted at point H by the maximum shear stress theory of failure (Tresca criterion) -220mm b 180mm c) The factors of safety at point H predicted by the maximum-distortion-energy theory (von Mises criterion) can be calculated as MPa By use of the virtual work method, determine the rotation and deflection at the end B. mm (Downward deflection is negative) x 10-3 radians (Positive rotation is in the anticlockwise direction)
A steel beam, of lengths a=4 m and b=4 m and a hollow box cross section, is supported by a hinge support A and roller support B, see Figure Q.1. The width and height of the cross section are 200 mm and 300 mm, respectively, and the wall thickness of the cross section is 5 mm. The beam is under a distributed load of the intensity that linearly varies from q=0 kN/m to q=4.4 kN/m for AB span; and is constant with q= 4.4 kN/m for BC span. The Young's modulus of steel is 200 GPa. Ay, v 9 Part A a 5 mm 200 mm Figure Q.1 300 mm B b C X Calculate: a) the vertical support reaction in support A. When sketching FBD, set the positive directions of both reactions in the positive direction of yaxis. Enter your answer in kN to three decimal places.
A steel beam, of lengths a = 5 m and b = 2 m and a hollow box cross section, is supported by a hinge support A and roller support B, see Figure Q.1. The width and height of the cross section are 200 mm and 300 mm, respectively, and the wall thickness of the cross section is 5 mm. The beam is under a distributed load of the intensity that linearly varies from q = 0 kN/m to q = 5 kN/m for AB span; and is constant with q = 5 kN/m for BC span. The Young’s modulus of steel is 200 GPa. Questions: 1. Calculate the vertical support reaction in support A. When sketching FBD, set the positive directions of both reactions in the positive direction of y axis. Enter your answer in kN to three decimal places. 2. Calculate the vertical support reaction in support B. Enter your answer in kN to two decimal places. 3. Calculate the value of the maximum bending moment in the beam. Enter your answer in kNm to three decimal places. Note: when deriving internal moment equations, use the following…
3. 4 For the beams shown in the figure below, L = 2m, P = 5000N, E = 70 GPa, I = 2x10-4 mª (a) Determine the deflection and rotation angle in the middle point. (b) Find reaction force and moment in B. A L 2 P 77 L 2 B
A steel cantilever beam, of length 2L, has an l-section, see Figure Q3. The cantilever beam is under a uniformly distributed load q = 290 kN/m applied in its vertical plane of symmetry at OA part of the span. The yield strength of the steel is [o] = 400 MPa; the Young's modulus E = 217 GPa. L= 1 m and the coordinates of Point H are x= 0 mm, y = -75 mm, z= 0 mm. y q A B X 20mm 10mm H 20mmi -220mm b 180mm
A steel beam, of lengths a= 6 m and b= 3 m and a hollow box cross section, is supported by a hinge support A and roller support B, see Figure Q.1. The width and height of the cross section are 200 mm and 300 mm, respectively, and the wall thickness of the cross section is 5 mm. The beam is under a distributed load of the intensity that linearly varies from q = 0 kN/m to q = 3.1 kN/m for AB span; and is constant with q= 3.1 kN/m for BC span. The Young's modulus of steel is 200 GPa. Part A Calculate: A y, v a 5 mm 200 mm Figure Q.1 9 S B 300 mm b с X
A beam supported by two identical springs at points A and B (see figure). Given that flexural of rigidity of the beam, EI= 2.029X1011 N.mm2 ; spring constant = 1471.5N/mm, distribution load w=116N/mm All dimensions are in mm. 1. What are the reaction force RA and RB? 2. Please draw shear-force and bending moment diagram.
A cylindrical pressure vessel with flat ends is subjected to a torque 7 and a bending moment M (see figure). ot oc max Zo = M yo The outer radius is 12.2 in. and the wall thickness is 1.0 in. The loads are T = 800 kip-in., M = 1,000 kip-in., and the internal pressure p = 840 psi. Determine the maximum tensile stress, maximum compressive stress and maximum shear stress Tmax in the wall of the cylinder. (Enter the magnitudes in psi. Assume that the structure behaves linearly elastically and that the stresses caused by two or more loads may be superimposed to obtain the resultant stresses acting at a point. Consider both in-plane and out-of-plane shear stresses unless otherwise specified.) T M psi хо 11474.4981 X Your response differs from the correct answer by more than 10%. Double check your calculations. psi 0 psi