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A solution of vinegar is 0.763 M in acetic acid, C2H4O2(molar mass = 60 g mol-1). The density of vinegar is 1.004 g/mL. What is the molal concentration of acetic acid?

A solution of vinegar is 0.763 M in acetic acid, C2H4O2(molar mass = 60 g mol-1). The density of vinegar is 1.004 g/mL. What is the molal concentration of acetic acid?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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  1. A solution of vinegar is 0.763 M in acetic acid, C2H4O2(molar mass = 60 g mol-1). The density of vinegar is 1.004 g/mL. What is the molal concentration of acetic acid?

 

 

  1. Phenols, HOC6H5 are weakly acidic, and in aqueous solution an equilibrium exists between the phenol and the phenoxide ion. Ka for HOC6H5 = 1.6 ×10-10.
  • What is the optimal pH for phenol buffers?

 

  • Consider 1.0 L of a solution that is 0.85 M HOC6H5 and 0.80 M NaOC6H5. Calculate the pH of this solution.

 

  • Calculate the pH after 0.10 mole of HCl has been added to the part (b) solution. Assume no volume change on addition of HCl.

 

 

  1. (a) The Ka of benzoic acid (C6H5CO2H，molar mass = 122 g·mol-1) is 6.46×10-5. A solution is

 

prepared by dissolving 6.1 g benzoic acid in enough water to make 1.0 L of solution. Calculate

 

[C6H5CO2H], [C6H5CO2–], [H+], [OH–], the pH and the percent ionization of this solution.

 

  • Sodium benzoate (NaC7H5O2) is used as a food preservative. What is the ratio of the concentration of benzoic acid to the concentration of benzoate ion in a food with pH = 3.00?

 

 

  1. Solution made by dissolving 6.73 grams of toluic acid in 110 grams of benzene (f.p. = 5.45oC, Kf = 5.07 oC/m) gave a freezing point of 3.00 o What is the calculated molecular weight of toluic acid form this data?

 

  1. Aluminum oxide forms when aluminum reacts with oxygen, 4 Al(s) + 3 O2(g) ➔ 2 Al2O3(s)

A mixture of 41.25 g of aluminum (Al, molar mass = 27 g·mol-1) and 58.65 g of oxygen (O2, molar mass = 32 g·mol-1) is allowed to react.

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