What is the pH of a 4.8 M pyridine solution that has Kp = 1.9 x 109? The equation for the dissociation of pyridine is C5H5N(aq) + H2O() : C5H5NH*(aq) + OH"(aq). 9.98 10.98 8.72 4.02

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**Question:**

What is the pH of a 4.8 M pyridine solution that has \( K_b = 1.9 \times 10^{-9} \)? The equation for the dissociation of pyridine is:

\[ \text{C}_5\text{H}_5\text{N(aq)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{C}_5\text{H}_5\text{NH}^+\text{(aq)} + \text{OH}^-\text{(aq)} \]

**Options:**

- ○ 9.98
- ○ 10.98
- ○ 8.72
- ○ 4.02
Transcribed Image Text:**Question:** What is the pH of a 4.8 M pyridine solution that has \( K_b = 1.9 \times 10^{-9} \)? The equation for the dissociation of pyridine is: \[ \text{C}_5\text{H}_5\text{N(aq)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{C}_5\text{H}_5\text{NH}^+\text{(aq)} + \text{OH}^-\text{(aq)} \] **Options:** - ○ 9.98 - ○ 10.98 - ○ 8.72 - ○ 4.02
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