The value of K, for nitrous acid is 4.50×10-4. What is the value of Kp, for its conjugate base, NO2"?

Appl Of Ms Excel In Analytical Chemistry
2nd Edition
ISBN:9781285686691
Author:Crouch
Publisher:Crouch
Chapter8: Polyfunctional Acids And Bases
Section: Chapter Questions
Problem 4P
icon
Related questions
icon
Concept explainers
Question
**Question:**

The value of \(K_a\) for nitrous acid is \(4.50 \times 10^{-4}\).

What is the value of \(K_b\), for its conjugate base, \(NO_2^-\)? 

**Answer:** 

To find the value of \(K_b\) for the conjugate base \(NO_2^-\), we can use the relationship between the acid dissociation constant (\(K_a\)) and the base dissociation constant (\(K_b\)) for a conjugate acid-base pair, which is given by:

\[ K_a \times K_b = K_w \]

where \(K_w\) is the ion-product constant for water. At 25°C, \(K_w\) is \(1.0 \times 10^{-14}\).

Given: 
\[ K_a = 4.50 \times 10^{-4} \]

We need to find \(K_b\):

\[ K_b = \frac{K_w}{K_a} \]

\[ K_b = \frac{1.0 \times 10^{-14}}{4.50 \times 10^{-4}} \]

\[ K_b = 2.22 \times 10^{-11} \]

Thus, the value of \(K_b\) for the conjugate base \(NO_2^-\) is \(2.22 \times 10^{-11}\).
Transcribed Image Text:**Question:** The value of \(K_a\) for nitrous acid is \(4.50 \times 10^{-4}\). What is the value of \(K_b\), for its conjugate base, \(NO_2^-\)? **Answer:** To find the value of \(K_b\) for the conjugate base \(NO_2^-\), we can use the relationship between the acid dissociation constant (\(K_a\)) and the base dissociation constant (\(K_b\)) for a conjugate acid-base pair, which is given by: \[ K_a \times K_b = K_w \] where \(K_w\) is the ion-product constant for water. At 25°C, \(K_w\) is \(1.0 \times 10^{-14}\). Given: \[ K_a = 4.50 \times 10^{-4} \] We need to find \(K_b\): \[ K_b = \frac{K_w}{K_a} \] \[ K_b = \frac{1.0 \times 10^{-14}}{4.50 \times 10^{-4}} \] \[ K_b = 2.22 \times 10^{-11} \] Thus, the value of \(K_b\) for the conjugate base \(NO_2^-\) is \(2.22 \times 10^{-11}\).
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Ionic Equilibrium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Appl Of Ms Excel In Analytical Chemistry
Appl Of Ms Excel In Analytical Chemistry
Chemistry
ISBN:
9781285686691
Author:
Crouch
Publisher:
Cengage
Chemistry: The Molecular Science
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry: Principles and Practice
Chemistry: Principles and Practice
Chemistry
ISBN:
9780534420123
Author:
Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning