A solution of phosphoric acid (H3PO4) with a known concentration of 0.250M H3PO4 is titrated with a 0.800 M NaOH solution. How many ml of NaOH are required to reach the third equivalence point with a starting volume of 72.0 mL H3PO4 according to the following balanced chemical equation: H3PO4 + NaOH Na3PO4 + H2O

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Chapter1: Chemical Foundations
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A solution of phosphoric acid (H3PO4) with a known concentration of 0.250M H;PO4
is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to
reach the third equivalence point with a starting volume of 72.0 mL H;PO4
according to the following balanced chemical equation:
H;PO4 +
3
NaOH
Na3PO4 +
3
H2O
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
%3D
43.2
72.0
6.75 x 104
22.5
0.250
1000
0.0675
2
3
7.50
67.5
0.001
0.800
mol H3PO4
L NaOH
g NaOH
LH;PO4
M H3PO4
M NaOH
g H;PO
+
mL H3PO4
mL NaOH
mol NaOH
Transcribed Image Text:A solution of phosphoric acid (H3PO4) with a known concentration of 0.250M H;PO4 is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 72.0 mL H;PO4 according to the following balanced chemical equation: H;PO4 + 3 NaOH Na3PO4 + 3 H2O STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) %3D 43.2 72.0 6.75 x 104 22.5 0.250 1000 0.0675 2 3 7.50 67.5 0.001 0.800 mol H3PO4 L NaOH g NaOH LH;PO4 M H3PO4 M NaOH g H;PO + mL H3PO4 mL NaOH mol NaOH
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