A solution of hydrocyanic acid is prepared by dissolving 0.10 mol HCN in enough water to make 1.0 L of solution. If 0.0050 mol of NaCN is added to the solution with no increase in volume, what is the concentration of H+ when equilibrium is re-established? The pH of the solution is 5.2 before adding 0.005 mol NaCN. (Hint: Use concentrations to get equilibrium constant. Account for the added CN- ions. Treat Na+ is a spectator ion) *final answer in 4 decimals
A solution of hydrocyanic acid is prepared by dissolving 0.10 mol HCN in enough water to make 1.0 L of solution. If 0.0050 mol of NaCN is added to the solution with no increase in volume, what is the concentration of H+ when equilibrium is re-established? The pH of the solution is 5.2 before adding 0.005 mol NaCN. (Hint: Use concentrations to get equilibrium constant. Account for the added CN- ions. Treat Na+ is a spectator ion) *final answer in 4 decimals
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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A solution of hydrocyanic acid is prepared by dissolving 0.10 mol HCN in
enough water to make 1.0 L of solution. If 0.0050 mol of NaCN is added to the solution
with no increase in volume, what is the concentration of H+ when equilibrium is re-established? The pH of the solution is 5.2 before adding 0.005 mol NaCN.
(Hint: Use concentrations to get equilibrium constant. Account for the added CN- ions. Treat Na+
is a spectator ion)
*final answer in 4 decimals
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