A solid constant-diameter circular shaft is subjected to the torques of TA = 470 Ib-ft, Te = 1090 lb ft, Tc = 840 Ib-ft, and Tp = 220 lb ft, acting in the directions shown. The bearings shown allow the shaft to turn freely. (a) Plot a torque diagram showing the internal torque in segments (1), (2), and (3) of the shaft. Use the sign convention presented in Section 6.6. (b) If the allowable shear stress in the shaft is 5200 psi, what is the minimum acceptable diameter for the shaft?
A solid constant-diameter circular shaft is subjected to the torques of TA = 470 Ib-ft, Te = 1090 lb ft, Tc = 840 Ib-ft, and Tp = 220 lb ft, acting in the directions shown. The bearings shown allow the shaft to turn freely. (a) Plot a torque diagram showing the internal torque in segments (1), (2), and (3) of the shaft. Use the sign convention presented in Section 6.6. (b) If the allowable shear stress in the shaft is 5200 psi, what is the minimum acceptable diameter for the shaft?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A solid constant-diameter circular shaft is subjected to the torques of TA = 470 Ib-ft, Te = 1090 lb ft, Tc = 840
Ib-ft, and Tp = 220 lb ft, acting in the directions shown. The bearings shown allow the shaft to turn freely.
(a) Plot a torque diagram showing the internal torque in segments (1), (2), and (3) of the shaft. Use the sign
convention presented in Section 6.6.
(b) If the allowable shear stress in the shaft is 5200 psi, what is the minimum acceptable diameter for the shaft?
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A solid constant-diameter circular shaft is subjected to the torques of TA = 470 lb-ft, TB = 1090 lb-ft, Tc = 840
lb-ft, and Tp = 220 lb-ft, acting in the directions shown. The bearings shown allow the shaft to turn freely.
(a) Plot a torque diagram showing the internal torque in segments (1), (2), and (3) of the shaft. Use the sign
convention presented in Section 6.6.
(b) If the allowable shear stress in the shaft is 5200 psi, what is the minimum acceptable diameter for the shaft?
TB
TD
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Answer:
(a) T₁ =
T₂=
T3 =
(b) d=
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(3)
lb-ft
lb-ft
lb-ft
in.
(2)
B
(1)
A
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