A solenoid is 60 cm long and 5.0 cm in diameter. It is tightly wound with a single layer öf 1.5-mm-diameter wire. Calculate what the magnetic field inside the solenoid would be when 3.0 A of current flows through the solenoid.

A solenoid is 60 cm long and 5.0 cm in diameter. It is tightly wound with a single layer öf 1.5-mm-diameter wire. Calculate what the magnetic field inside the solenoid would be when 3.0 A of current flows through the solenoid.

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Question

i have the question in the pictrue please i need simple solution and answer

thank you

A solenoid is 60 cm long and 5.0 cm in diameter. It is tightly wound with a single
layer öf 1.5-mm-diameter wire. Calculate what the magnetic field inside the
solenoid would be when 3.0 A of current flows through the solenoid.

Expert Solution

Step 1

A solenoid is an electromagnet. It is a coil of tightly wound conducting wires around an iron core that generates a magnetic field whenever current passes through the wire.

The magnetic field inside a solenoid is given as

$B = μ_{o} \frac{N}{L} I μ_{o} i s t h e p e r m e a b i l i t y o f f r e e s p a c e = 4 π \times 10^{- 7} N i s t h e n u m b e r o f t u r n s i n t h e s o l e n o i d c o i l L i s t h e l e n g t h o f t h e s o l e n o i d T h e n u m b e r o f t u r n s i n t h e s o l e n o i d i s t h e r a t i o o f t h e l e n g t h o f t h e s o l e n o i d t o t h e d i a m e t e r o f t h e w i r e w o u d n a r o u n d t h e s o l e n o i d N = \frac{60}{0.15} N = 400$

Step 2

$B = μ_{o} \frac{N}{L} I B = 4 π \times 10^{- 7} \times \frac{400}{60 \times 10^{- 2}} \times 3 B = 2.5 \times 10^{- 3} T$

This is the magnitude of the magnetic field present inside the solenoid

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