A solenoid is 60 cm long and 5.0 cm in diameter. It is tightly wound with a single layer öf 1.5-mm-diameter wire. Calculate what the magnetic field inside the solenoid would be when 3.0 A of current flows through the solenoid.

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A solenoid is 60 cm long and 5.0 cm in diameter. It is tightly wound with a single
layer öf 1.5-mm-diameter wire. Calculate what the magnetic field inside the
solenoid would be when 3.0 A of current flows through the solenoid.
Transcribed Image Text:A solenoid is 60 cm long and 5.0 cm in diameter. It is tightly wound with a single layer öf 1.5-mm-diameter wire. Calculate what the magnetic field inside the solenoid would be when 3.0 A of current flows through the solenoid.
Expert Solution
Step 1

A solenoid is an electromagnet. It is a coil of tightly wound conducting wires around an iron core that generates a magnetic field whenever current passes through the wire.

The magnetic field inside a solenoid is given as

B=μoNLIμo is the permeability of free space=4π×10-7N is the number of turns in the solenoid coilL is the length of the solenoidThe number of turns in the solenoid is the ratio of the length of the solenoid to the diameter of the wire woudn around the solenoidN=600.15N=400

Step 2

B=μoNLIB=4π×10-7×40060×10-2×3B=2.5×10-3T

This is the magnitude of the magnetic field present inside the solenoid

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