A small 12.0 g plastic ball is tied to a very light 25.7 cm stringthat is attached to the vertical wall of a room. (See the figure (Figure 1).) A uniform horizontal electric field exists in thisroom. When the ball has been given an excess charge of-1.20 μC, you observe that it remains suspended, with thestring making an angle of 17.4° with the wall.Figure17.4°1 of 1Part AFind the magnitude of the electric field in the room.Express your answer in newtons per coulomb.ΠΙΑΣΦE =SubmitPart BX Incorrect; Try Again; 4 attempts remainingPrevious Answers Request AnswerFind the direction of the electric field in the room.to the leftto the rightSubmitProvide FeedbackPrevious AnswersCorrect?PearsonN/C<Next >

A small 12.0 g plastic ball is tied to a very light 25.7 cm string that is attached to the vertical wall of a room. (See the figure ( Figure 1).) A uniform horizontal electric field exists in this room. When the ball has been given an excess charge of -1.20 μC, you observe that it remains suspended, with the string making an angle of 17.4° with the wall. Figure 17.4° 1 of 1 Find the magnitude of the electric field in the room. Express your answer in newtons per coulomb. IVE ΑΣΦ E= Submit Previous Answers Request Answer * Incorrect; Try Again; 4 attempts remaining Part B Find the direction of the electric field in the room. to the left to the right Submit Previous Answers ✓ Correct Provide Feedback ? N/C

A small 12.0 g plastic ball is tied to a very light 25.7 cm string that is attached to the vertical wall of a room. (See the figure ( Figure 1).) A uniform horizontal electric field exists in this room. When the ball has been given an excess charge of -1.20 μC, you observe that it remains suspended, with the string making an angle of 17.4° with the wall. Figure 17.4° 1 of 1 Find the magnitude of the electric field in the room. Express your answer in newtons per coulomb. IVE ΑΣΦ E= Submit Previous Answers Request Answer * Incorrect; Try Again; 4 attempts remaining Part B Find the direction of the electric field in the room. to the left to the right Submit Previous Answers ✓ Correct Provide Feedback ? N/C

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A charged cork ball of mass 1.10 g is suspended on a light string in the presence of a uniform electric field as shown in the figure below. When E = (2.80 î + 5.20 ĵ) ✕ 105 N/C, the ball is in equilibrium at θ = 37.0°. Find the charge on the ball.
NU PHYS101C: Physic I(F ... Nile University Question 19 A small, 2 g plastic ball carrying a charge q = - 50µC is suspended by a 20 cm long string in a uniform electric field. If the ball is in equilibrium when 0= 60°, then E = Not yet answered Marked out of 1.00 P Flag question 20.0 cm M= 2.00 g Select one: O a. 6.79 (-i) O b. 6.79 (i) O . 2.26 () O d. 2.26 (-i) O e. 2.26 (i) P Type here to search Ps Lr 立

Determine the magnitude of the electric field.
could you solve this
The figure below shows two identical small, charged spheres. One of mass 4.3 g is hanging by an insulating thread of length 20.0 cm. The other is held in place and has charge q₁ = -3 -3.1 μC. The thread makes an angle of 18° with the vertical, resulting in the spheres being aligned horizontally, a distance r apart. Determine the charge 92 on the hanging sphere. nC 20.0 cm 18⁰ 91 92 ✈
Hi sir, pllleeaassee soolvee this questionnn, thanks a lot for ur effects
A thin rod of length L=6.7 m carries a uniform charge q=6.1 μC along its length. Take Coulomb's constant as k=9 x 109 N m2 / C2. Determine the magnitude of the electric field at point A. Express your answer using 1 decimal place without entering the units.
B7
A charged cork ball of mass 2.50 g is suspended on a light string in the presence of a uniform electric field as shown in the figure below. When E = (2.00 î + 4.60 ĵ) ✕ 105 N/C, the ball is in equilibrium at ? = 37.0°. Find the charge on the ball. Find the tension in the string.
What must the charge (sign and magnitude) of a 2.45 g particle be for it to remain stationary when placed in a downward-directed electric field of magnitude 650 N/C ? Express your answer in microcoulombs.
Problem 12: A simple and common technique for accelerating electrons is shown in the figure, which depicts a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through. E = 2.4 × 104 N/C Calculate the horizontal component of the electron's acceleration if the field strength is 2.4 × 104 N/C. Express your answer in meters per second squared, and assume the electric field is pointing in the negative x-direction as shown in the figure.
Four charges of equal magnitude 4.87 C are arranged at the corners of a square of side 6.93 cm as shown in the Figure. Notice that some charges have "-" sign. Find the magnitude of the electric field at the midpoint of one of the sides of the square. (Your result must be in multiples of 1013 N/C. That means if you get a result of 9.22x1013 just type 9.22 in the answer box. Include 2 digits after the decimal point and maximum of 5% of error is accepted in your answer. Take k=9x10⁹.) - O -- +9 +9 -7