A small 12.0 g plastic ball is tied to a very light 25.7 cm string that is attached to the vertical wall of a room. (See the figure ( Figure 1).) A uniform horizontal electric field exists in this room. When the ball has been given an excess charge of -1.20 μC, you observe that it remains suspended, with the string making an angle of 17.4° with the wall. Figure 17.4° 1 of 1 Find the magnitude of the electric field in the room. Express your answer in newtons per coulomb. IVE ΑΣΦ E= Submit Previous Answers Request Answer * Incorrect; Try Again; 4 attempts remaining Part B Find the direction of the electric field in the room. to the left to the right Submit Previous Answers ✓ Correct Provide Feedback ? N/C

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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A small 12.0 g plastic ball is tied to a very light 25.7 cm string
that is attached to the vertical wall of a room. (See the figure (
Figure 1).) A uniform horizontal electric field exists in this
room. When the ball has been given an excess charge of
-1.20 μC, you observe that it remains suspended, with the
string making an angle of 17.4° with the wall.
Figure
17.4°
1 of 1
Part A
Find the magnitude of the electric field in the room.
Express your answer in newtons per coulomb.
ΠΙΑΣΦ
E =
Submit
Part B
X Incorrect; Try Again; 4 attempts remaining
Previous Answers Request Answer
Find the direction of the electric field in the room.
to the left
to the right
Submit
Provide Feedback
Previous Answers
Correct
?
Pearson
N/C
<
Next >
Transcribed Image Text:A small 12.0 g plastic ball is tied to a very light 25.7 cm string that is attached to the vertical wall of a room. (See the figure ( Figure 1).) A uniform horizontal electric field exists in this room. When the ball has been given an excess charge of -1.20 μC, you observe that it remains suspended, with the string making an angle of 17.4° with the wall. Figure 17.4° 1 of 1 Part A Find the magnitude of the electric field in the room. Express your answer in newtons per coulomb. ΠΙΑΣΦ E = Submit Part B X Incorrect; Try Again; 4 attempts remaining Previous Answers Request Answer Find the direction of the electric field in the room. to the left to the right Submit Provide Feedback Previous Answers Correct ? Pearson N/C < Next >
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