Problem 2: A point mass of charge q> 0 moves at 35° to a uniform electric field E for a total distance d. Part (a) Select a diagram that follows from the problem description. y-axis y-axis yaxis y,-0 v qE E E E y-axis Y2 E Part (b) The charge q travels from point y, to point y2, where the total traveled distance is d. Find the potential difference that the charge traverse Vhen you enter your answer you can assume thaty = 0. Part (c) If the charge q = 7.79 µC, distance d= 21.2 m and the field magnitude E = 11.9 V/m, what is the work needed to keep the charge on its ngled trajectory? Answer in joules.

icon
Related questions
Question
Problem 2: A point mass of charge q> 0 moves at 35° to a uniform electric field E for a total distance d.
Part (a) Select a diagram that follows from the problem description.
y-axis
y-axis
y-axis
y,=0
v + qE
Y2
E
E
E
qE
y-axis
y,=0
E
Part (b) The charge q travels from point y, to point y, where the total traveled distance is d. Find the potential difference that the charge traverses.
When you enter your answer you can assume that y, = 0.
Part (c) If the charge q = 7.79 µC, distance d= 21.2 m and the field magnitude E = 11.9 V/m, what is the work needed to keep the charge on its
angled trajectory? Answer in joules.
Transcribed Image Text:Problem 2: A point mass of charge q> 0 moves at 35° to a uniform electric field E for a total distance d. Part (a) Select a diagram that follows from the problem description. y-axis y-axis y-axis y,=0 v + qE Y2 E E E qE y-axis y,=0 E Part (b) The charge q travels from point y, to point y, where the total traveled distance is d. Find the potential difference that the charge traverses. When you enter your answer you can assume that y, = 0. Part (c) If the charge q = 7.79 µC, distance d= 21.2 m and the field magnitude E = 11.9 V/m, what is the work needed to keep the charge on its angled trajectory? Answer in joules.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Similar questions