D - Capacitance Problem 3: Two parallel plates have charges +Q and −Q, as shown. The magnitude of the charges is 29.7nC, the area of each plate is A=0.0105 m2, and the distance between them is d=8.53cm. The plates are surrounded by air. Part (f) If the area is doubled to 2A while the gap is decreased to 14d, then what is the value, in picofarads, of the new capacitance? Part (g) What is the new value, in volts, of potential difference between the plates with the original charges, +Q and −Q, given the increased area and reduced gap of Part (f)?
D - Capacitance Problem 3: Two parallel plates have charges +Q and −Q, as shown. The magnitude of the charges is 29.7nC, the area of each plate is A=0.0105 m2, and the distance between them is d=8.53cm. The plates are surrounded by air. Part (f) If the area is doubled to 2A while the gap is decreased to 14d, then what is the value, in picofarads, of the new capacitance? Part (g) What is the new value, in volts, of potential difference between the plates with the original charges, +Q and −Q, given the increased area and reduced gap of Part (f)?
Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter23: Electric Fields
Section: Chapter Questions
Problem 23.2P: (a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of...
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D - Capacitance
Problem 3: Two parallel plates have charges +Q and −Q, as shown. The magnitude of the charges is 29.7nC, the area of each plate is A=0.0105 m2, and the distance between them is d=8.53cm. The plates are surrounded by air.
Part (f) If the area is doubled to 2A while the gap is decreased to 14d, then what is the value, in picofarads, of the new capacitance?
Part (g) What is the new value, in volts, of potential difference between the plates with the original charges, +Q and −Q, given the increased area and reduced gap of Part (f)?
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