**Problem 5:**A small **insulating solid sphere** with radius \( a \) is concentric with a larger **conducting spherical shell** with inner radius \( b \) and outer radius \( c \). The solid sphere has a total charge \(-5q\) distributed uniformly over its entire volume, and the spherical shell has charge \(-3q\). **Tasks:**(a) Using Gauss’s law, find the **electric field** (i) for \( r < a \) and (ii) for \( r > c \). Make sure to start with Gauss’s law.(b) What are the charges on (i) the inner and (ii) outer surface of the conducting shell?**Gauss's Law:**\[\Phi_E = \oint \mathbf{E} \cdot d\mathbf{A} = \frac{Q_{\text{enc}}}{\varepsilon_0}\]**Diagram Explanation:**The diagram shows three concentric circles. The innermost circle is labeled with radius \( a \), representing the insulating solid sphere. Surrounding it is a ring labeled with inner radius \( b \) and outer radius \( c \), representing the conducting spherical shell. The diagram illustrates the concentric nature of the sphere and shell.

Given, The total charge on the sphere, Qsp=-5q the total charge on the spherical shell, Qsh=-3q The…

Answered: 5. A small insulating solid sphere with…

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