A spherical shell insulator is shown in cross-section in the figure. It has inner radius a, outer radius b, and the point P is located a distance r from the origin. The shell has a total charge Q uniformly distributed throughout its volume. Which is a correct use of Gauss's law to find the magnitude of the electric field E at point P?
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A: As per guidelines we are supposed to answer only the first three subparts of the multipart question.…
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A: Given that: Charge,q= - 4.25 fC = -4.25 × 10-15 C Length of rod L= 0.0829 m distance from the rod a…
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- In the figure a sphere, of radius a = 13.2 cm and charge q = 6.00×10-6 C uniformly distributed throughout its volume, is concentric with a spherical conducting shell of inner radius b = 37.0 cm and outer radius c = 39.0 cm . This shell has a net charge of -q. Find expressions for the electric field, as a function of the radius r, within the sphere and the shell (r< a). Evaluate for r=6.6 cm. Find expressions for the electric field as a function of the radius r, between the sphere and the shell (a< r <b). Evaluate for r=25.1 cm. Find expressions for the electric field as a function of the radius r, inside the shell (b< r <c). Evaluate for r=38.0 cmA charge of Q is distributed as a quarter circle of a radius R. Lambda(theta)= lambda 0 sin theta provides the linear charge density where theta = 0 degrees along the positive x-axis. How would you find the constant of lambda in terms of Q and R, and what would the magnitude of the electric field be equal to at the center point?Five charged particles are equally spaced around a semicircle of radius 100 mm, with one particle at each end of the semicircle and the remaining three spaced equally between the two ends. The semicircle lies in the region x<0 of an xy plane, such that the complete circle is centered on the origin. If each particle carries a charge of 6.00 nC , what is the electric field at the origin? Where could you put a single particle carrying a charge of -5.00 nC to make the electric field magnitude zero at the origin?
- A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge per unit length of λ, and the cylinder has a net charge per unit length of 2λ. From this information, use Gauss’s law to find (a) the charge per unit length on the inner surface of the cylinder, (b) the charge per unit length on the outer surface of the cylinder, and (c) the electric field outside the cylinder a distance r from the axis.In Figure (a) below, a particle of charge +Q produces an electric field of magnitude Epart at point P, at distance R from the particle. In Figure (b), that same amount of charge is spread uniformly along a circular arc that has radius R and subtends an angle 8. The charge on the arc produces an electric field of magnitude Earc at its center of curvature P. For what value of 0 (in º) does Earc = 0.75Epart? (Hint: You will probably resort to a graphical solution.) +Q |▬▬▬R—-|| Number i P (a) AR +Q}/0/2/ (b) Units ° (degree:A thin, copper washer of inner radius R = 54.0 mm and width d = 27.0 mm carries a unformly distributed total charge Q-9.00 nC. Determine the z-component of the electric field, Ez, due to the washer at a distance z = 12.0 cm along the washer's symmetry axis. Ez = -7.99 ×104 Incorrect N/C y Z
- A cube has positive charge +Q in all corners except for one, which has a negative point charge - Q. Let the distance from any corner to the center of the cube be r. What is the magnitude and direction of the of electric field at the center of the cube (point P)?A thin, circular disk of radius R = 45 cm is oriented in the yz-plane with its center as the origin. The disk carries a total charge Q = 6.0 μC distributed uniformly over its surface. Calculate the magnitude of the electric field due to the disk at the point x = 12 cm along the x-axis.