In this problem, we will apply Gauss's law to a conducting shell that surrounds a charge. This problem is spherically symmetric, which makes it an ideal candidate for a Gauss's law analysis. A hollow conductor carries a net charge of +7 nC. In its cavity, insulated from the conductor, is a small, isolated sphere with a net charge of -5 nC. How much charge is on the outer surface of the hollow conductor? How much is on the inner surface of the cavity? Figure Net charge - +7 nC +5 nC on cavity wall Gaussian surface +2 nC on outer surface 1 of 1 > SOLUTION SET UP (Figure 1) shows our sketch. We know that in this electrostatic situation the electric field in the conducting material must be zero. We draw a Gaussian surface within the material of the conductor and apply Gauss's law. SOLVE We apply Gauss's law g = Qenel/€o to the Gaussian surface shown in (Figure 1). The Gaussian surface lies within the conducting material, so E = 0 everywhere on that surface. By Gauss's law, g = Qencl/co. Thus, g = 0, so Qencl = 0. But then, in order to have Qencl = 0, there must be a charge of +5 nC on the inner surface of the cavity, to cancel the charge in the cavity. The conductor carries a total charge of +7 nC, and all of its net charge is on its surfaces. So, if there is +5 nC on the inner surface, the remaining +2 nC must be on the outer surface, as shown in our sketch. REFLECT Field lines pass between the +5 nC on the inner surface of the cavity and the -5 nC on the object in the cavity. Each field line going to the-5 nC charge originated on the +5 nC charge; the field lines don't continue into the conducting material because E=0 there. There is an electric field outside the conductor due to the +2 nC on its surface. ▾ Part A - Practice Problem: Determine the charge on the outer surface of the hollow conductor for the case where the conductor has a net charge of +2 nC. Express your answer in nanocoulombs. ΠΫΠΙ ΑΣΦ q= Submit ▾ Part B - Practice Problem: Request Answer q= Submit → Determine the charge on the inner surface of the cavity for the case where the conductor has a net charge of +2 nC. Express your answer in nanocoulombs. [95] ΑΣΦΑ @ Request Answer C ? nC C Q ? nC
In this problem, we will apply Gauss's law to a conducting shell that surrounds a charge. This problem is spherically symmetric, which makes it an ideal candidate for a Gauss's law analysis. A hollow conductor carries a net charge of +7 nC. In its cavity, insulated from the conductor, is a small, isolated sphere with a net charge of -5 nC. How much charge is on the outer surface of the hollow conductor? How much is on the inner surface of the cavity? Figure Net charge - +7 nC +5 nC on cavity wall Gaussian surface +2 nC on outer surface 1 of 1 > SOLUTION SET UP (Figure 1) shows our sketch. We know that in this electrostatic situation the electric field in the conducting material must be zero. We draw a Gaussian surface within the material of the conductor and apply Gauss's law. SOLVE We apply Gauss's law g = Qenel/€o to the Gaussian surface shown in (Figure 1). The Gaussian surface lies within the conducting material, so E = 0 everywhere on that surface. By Gauss's law, g = Qencl/co. Thus, g = 0, so Qencl = 0. But then, in order to have Qencl = 0, there must be a charge of +5 nC on the inner surface of the cavity, to cancel the charge in the cavity. The conductor carries a total charge of +7 nC, and all of its net charge is on its surfaces. So, if there is +5 nC on the inner surface, the remaining +2 nC must be on the outer surface, as shown in our sketch. REFLECT Field lines pass between the +5 nC on the inner surface of the cavity and the -5 nC on the object in the cavity. Each field line going to the-5 nC charge originated on the +5 nC charge; the field lines don't continue into the conducting material because E=0 there. There is an electric field outside the conductor due to the +2 nC on its surface. ▾ Part A - Practice Problem: Determine the charge on the outer surface of the hollow conductor for the case where the conductor has a net charge of +2 nC. Express your answer in nanocoulombs. ΠΫΠΙ ΑΣΦ q= Submit ▾ Part B - Practice Problem: Request Answer q= Submit → Determine the charge on the inner surface of the cavity for the case where the conductor has a net charge of +2 nC. Express your answer in nanocoulombs. [95] ΑΣΦΑ @ Request Answer C ? nC C Q ? nC
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
![In this problem, we will apply Gauss's law to a conducting shell that surrounds a
charge. This problem is spherically symmetric, which makes it an ideal
candidate for a Gauss's law analysis. A hollow conductor carries a net charge of
+7 nC. In its cavity, insulated from the conductor, is a small, isolated sphere
with a net charge of -5 nC. How much charge is on the outer surface of the
hollow conductor? How much is on the inner surface of the cavity?
Figure
Net charge
= +7 nC
+5 nC on
cavity wall
Gaussian
surface
+2 nC on
outer surface
1 of 1
SOLUTION
SET UP (Figure 1) shows our sketch. We know that in this electrostatic situation the electric field in the conducting material must be zero. We draw a Gaussian surface within the material of the
conductor and apply Gauss's law.
SOLVE We apply Gauss's law PE = Qencl/€o to the Gaussian surface shown in (Figure 1). The Gaussian surface lies within the conducting material, so E = 0 everywhere on that surface. By
Gauss's law, E = Qencl/€0. Thus, PE = 0, so Qencl = 0. But then, in order to have Qencl = 0, there must be a charge of +5 nC on the inner surface of the cavity, to cancel the charge in the
cavity. The conductor carries a total charge of +7 nC, and all of its net charge is on its surfaces. So, if there is +5 nC on the inner surface, the remaining +2 nC must be on the outer surface, as
shown in our sketch.
REFLECT Field lines pass between the +5 nC on the inner surface of the cavity and the -5 nC on the object in the cavity. Each field line going to the-5 nC charge originated on
the +5 nC charge; the field lines don't continue into the conducting material because E = 0 there. There is an electric field outside the conductor due to the +2 nC on its surface.
Part A - Practice Problem:
Determine the charge on the outer surface of the hollow conductor for the case where the conductor has a net charge of +2 nC.
Express your answer in nanocoulombs.
—| ΑΣΦ
q=
Submit
Part B - Practice Problem:
Request Answer
q=
Submit
Determine the charge on the inner surface of the cavity for the case where the conductor has a net charge of +2 nC.
Express your answer in nanocoulombs.
VE ΑΣΦ
?
Request Answer
nC
?
nC](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd08e19be-7e5e-4944-9492-2c1f0e254c97%2F58313a2d-9c25-4d80-a4ce-d7b6129cbe9a%2Fagb89mb_processed.png&w=3840&q=75)
Transcribed Image Text:In this problem, we will apply Gauss's law to a conducting shell that surrounds a
charge. This problem is spherically symmetric, which makes it an ideal
candidate for a Gauss's law analysis. A hollow conductor carries a net charge of
+7 nC. In its cavity, insulated from the conductor, is a small, isolated sphere
with a net charge of -5 nC. How much charge is on the outer surface of the
hollow conductor? How much is on the inner surface of the cavity?
Figure
Net charge
= +7 nC
+5 nC on
cavity wall
Gaussian
surface
+2 nC on
outer surface
1 of 1
SOLUTION
SET UP (Figure 1) shows our sketch. We know that in this electrostatic situation the electric field in the conducting material must be zero. We draw a Gaussian surface within the material of the
conductor and apply Gauss's law.
SOLVE We apply Gauss's law PE = Qencl/€o to the Gaussian surface shown in (Figure 1). The Gaussian surface lies within the conducting material, so E = 0 everywhere on that surface. By
Gauss's law, E = Qencl/€0. Thus, PE = 0, so Qencl = 0. But then, in order to have Qencl = 0, there must be a charge of +5 nC on the inner surface of the cavity, to cancel the charge in the
cavity. The conductor carries a total charge of +7 nC, and all of its net charge is on its surfaces. So, if there is +5 nC on the inner surface, the remaining +2 nC must be on the outer surface, as
shown in our sketch.
REFLECT Field lines pass between the +5 nC on the inner surface of the cavity and the -5 nC on the object in the cavity. Each field line going to the-5 nC charge originated on
the +5 nC charge; the field lines don't continue into the conducting material because E = 0 there. There is an electric field outside the conductor due to the +2 nC on its surface.
Part A - Practice Problem:
Determine the charge on the outer surface of the hollow conductor for the case where the conductor has a net charge of +2 nC.
Express your answer in nanocoulombs.
—| ΑΣΦ
q=
Submit
Part B - Practice Problem:
Request Answer
q=
Submit
Determine the charge on the inner surface of the cavity for the case where the conductor has a net charge of +2 nC.
Express your answer in nanocoulombs.
VE ΑΣΦ
?
Request Answer
nC
?
nC
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you
![College Physics](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
![University Physics (14th Edition)](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
![Introduction To Quantum Mechanics](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
![College Physics](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
![University Physics (14th Edition)](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
![Introduction To Quantum Mechanics](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
![Physics for Scientists and Engineers](https://www.bartleby.com/isbn_cover_images/9781337553278/9781337553278_smallCoverImage.gif)
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
![Lecture- Tutorials for Introductory Astronomy](https://www.bartleby.com/isbn_cover_images/9780321820464/9780321820464_smallCoverImage.gif)
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
![College Physics: A Strategic Approach (4th Editio…](https://www.bartleby.com/isbn_cover_images/9780134609034/9780134609034_smallCoverImage.gif)
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON