Below is a solid sphere of insulating materials (meaning that once placed, charge will not move around even when it feels a force).  This sphere has a changing charge density given by the equation below.  This tells you that there is more charge near the outer edges (when r is larger) then near the center (when r is small) since the charge density is proportional to r^2. In the image R is the total radius of the sphere and r is the distance from the center you will be asked about.  There values are below.  You have to calculate the amount of charge enclosed with the radius of r to find the electric field.  You'll need to integrate to do this - that's where the charge density equation below will be used. Use Gauss's Law to find the Electric Field magnitude at a distance r from the center of the sphere.  Make sure to think about charge enclosed and how to find it.  It is a little more complicated in this problem.  Be careful with your 2 radial values (R and r).

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Below is a solid sphere of insulating materials (meaning that once placed, charge will not move around even when it feels a force).  This sphere has a changing charge density given by the equation below.  This tells you that there is more charge near the outer edges (when r is larger) then near the center (when r is small) since the charge density is proportional to r^2.

In the image R is the total radius of the sphere and r is the distance from the center you will be asked about.  There values are below.  You have to calculate the amount of charge enclosed with the radius of r to find the electric field.  You'll need to integrate to do this - that's where the charge density equation below will be used.

Use Gauss's Law to find the Electric Field magnitude at a distance r from the center of the sphere.  Make sure to think about charge enclosed and how to find it.  It is a little more complicated in this problem.  Be careful with your 2 radial values (R and r).

p = Por2
R
nC
Po = 25.0-
m5
R = 1.60 m
r = 0.650 m
Transcribed Image Text:p = Por2 R nC Po = 25.0- m5 R = 1.60 m r = 0.650 m
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