A small 12.0 g plastic ball is tied to a very light 25.7 cm string that is attached to the vertical wall of a room. (See the figure ( Figure 1).) A uniform horizontal electric field exists in this room. When the ball has been given an excess charge of -1.20 μC, you observe that it remains suspended, with the string making an angle of 17.4° with the wall. Figure 1 of 1 ▾ Part A Find the magnitude of the electric field in the room. Express your answer in newtons per coulomb. ID ΑΣΦ E= Submit Part B Request Answer Find the direction of the electric field in the room. to the left g ? N/C

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
A small 12.0 g plastic ball is tied to a very light 25.7 cm string
that is attached to the vertical wall of a room. (See the figure (
Figure 1).) A uniform horizontal electric field exists in this
room. When the ball has been given an excess charge of
-1.20 μC, you observe that it remains suspended, with the
string making an angle of 17.4° with the wall.
Figure
17.4°
1 of 1
Part A
Find the magnitude of the electric field in the room.
Express your answer in newtons per coulomb.
E =
Submit
Part B
Find the direction of the electric field in the room.
to the left
Request Answer
to the right
Submit
ΑΣΦ
Provide Feedback
Request Answer
?
N/C
Next >
Transcribed Image Text:A small 12.0 g plastic ball is tied to a very light 25.7 cm string that is attached to the vertical wall of a room. (See the figure ( Figure 1).) A uniform horizontal electric field exists in this room. When the ball has been given an excess charge of -1.20 μC, you observe that it remains suspended, with the string making an angle of 17.4° with the wall. Figure 17.4° 1 of 1 Part A Find the magnitude of the electric field in the room. Express your answer in newtons per coulomb. E = Submit Part B Find the direction of the electric field in the room. to the left Request Answer to the right Submit ΑΣΦ Provide Feedback Request Answer ? N/C Next >
Expert Solution
Step 1 GIVEN

Mass, m = 12 g = 12×10-3 kg = 0.012 kg

Length, l = 25.7 cm 

Charge, q = -1.20 µC = -1.20×10-6 C

Angle, θ = 17.4°

 

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Knowledge Booster
Electric field
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON