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A site is being considered for wind power generation. At this site, the wind blows steadily at 6 m/s for 3,323 hours per year. Assuming the wind velocity is negligible at other times for simplicity, determine the kWh/year that can be produced at the site for a turbine with a mechanical efficiency of 100% and an effective flow area of 5 m2. Use a value of 1.25 kg/m3 for the density of the air. Give your answer in killowatt-hours per year (kWh/year). Hint: I reccomend starting by finding the kinetic energy (kJ/kg) of the wind. Hint 2: Multiply the power generation (kW) by the number of hours of wind per year (h/year) to get kWh/year

A site is being considered for wind power generation. At this site, the wind blows steadily at 6 m/s for 3,323 hours per year. Assuming the wind velocity is negligible at other times for simplicity, determine the kWh/year that can be produced at the site for a turbine with a mechanical efficiency of 100% and an effective flow area of 5 m2. Use a value of 1.25 kg/m3 for the density of the air. Give your answer in killowatt-hours per year (kWh/year). Hint: I reccomend starting by finding the kinetic energy (kJ/kg) of the wind. Hint 2: Multiply the power generation (kW) by the number of hours of wind per year (h/year) to get kWh/year

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A site is being considered for wind power generation. At this site, the wind blows steadily at 6 m/s for 3,323 hours per year. Assuming the wind velocity is negligible at other times for simplicity, determine the kWh/year that can be produced at the site for a turbine with a mechanical efficiency of 100% and an effective flow area of 5 m2. Use a value of 1.25 kg/m3 for the density of the air. Give your answer in killowatt-hours per year (kWh/year).

Hint: I reccomend starting by finding the kinetic energy (kJ/kg) of the wind.

Hint 2: Multiply the power generation (kW) by the number of hours of wind per year (h/year) to get kWh/year.

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