A Single-phase, 300 KVA, MKV/ 2.2kV, 60 Hz transformer has the following equivalent circuit parameters referred to the high-voltage Side: RACHY = 57.6K√2 Xm HV Req, HV X eq HV = 16-34 kv = 2.784 № = 8.455 a) Determine i-No-load Current as -No-load power loss (ie the love loss). ãi - No load iv - Full-load loss). a percentage of full-load current power factor. Copper loss Cie Copper b) If the load impedance ге on the low-voltage side is Zload = 16460°r. determine the voltage regulation using the approximate circuit.

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Please can you help with detail explanation i have no knowledge here please
A Single-phase, 300 KVA, MKV/ 2.2KV, 60 Hz transformer has the
following equivalent circuit parameters referred to the high-voltage
Side:
RCHV = 57.6k√2
Xm Hv
hey, HV
X eq HV
= 16-34 kv
= 2.784√№
= 8.455
a) Determine
i-No-load Current as
-No-load power loss (ie the love loss).
ui-No-load
iv - Full-load
Copper
loss).
b) If the load impedance on the low-voltage side is
Zload = 16460°2. determine the voltage regulation using
the approximate circuit.
a
percentage of full-load Current
power factor.
Copper
loss Cie
Transcribed Image Text:A Single-phase, 300 KVA, MKV/ 2.2KV, 60 Hz transformer has the following equivalent circuit parameters referred to the high-voltage Side: RCHV = 57.6k√2 Xm Hv hey, HV X eq HV = 16-34 kv = 2.784√№ = 8.455 a) Determine i-No-load Current as -No-load power loss (ie the love loss). ui-No-load iv - Full-load Copper loss). b) If the load impedance on the low-voltage side is Zload = 16460°2. determine the voltage regulation using the approximate circuit. a percentage of full-load Current power factor. Copper loss Cie
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