Answered: Hello there. To start off, I AM BLIND…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Related questions

Question

Hello there. To start off, I AM BLIND AND CAN NOT READ IMAGES YOU MAY ATTEMPT TO RESPOND WITH. Please do not do that, it wastes your time and mine and would just like it written out in text like what you are reading right now. Thank you for understand.

So the question I am working on I have 1 part left and am not sure on how to calculate the final part.

THE DESCRIPTION TELLS ME :

A CIRCUIT INCLUDES 9 capacitors. The circuit has end points A and B. Capacitor C Capacitor C_1 is next to point A. Another capacitor c_1 is next to point B. Between these two capacitors, capacitor c_2 is connected parallel with the following combination. capacitor c_1 is between c_2 and point C. on the other side of c_2, another capacitor c_1 is between c_2 and point D.There are two parallel branches between points C and D. There is one more capacitor c_2 on the first branch, and there are three capacitors c_1 in series on the second branch.

that is it

The question goes:

In (Figure 1), each capacitance C1C1 is 6.6 μFμF, and each capacitance C2C2 is 4.4 μFμF.

Figure

1 of 1

Part A

Part complete

Compute the equivalent capacitance of the network between points aa and bb.

Express your answer in farads.

CeqCeq =

2.2×10⁻⁶

Got this one correct.

Part B

Part complete

Compute the charge on the capacitor C1C1 nearest to aa when VabVab = 500 VV.

Express your answer in coulombs.

Qa1Q1a =

1.1×10⁻³

This one is correct to.

Part C

Part complete

Compute the charge on the capacitor C1C1 nearest to bb when VabVab = 500 VV.

Express your answer in coulombs.

Qb1Q1b =

1.1×10⁻³

THIS ONE WAS CORRECT TOO.

Part D

Part complete

Compute the charge on the capacitor C2C2 nearest to aa and bb when VabVab = 500 VV.

Express your answer in coulombs.

Q2Q2 =

7.3×10⁻⁴

THIS ONE I GOT CORRECT TOO AND YOU DON'T NEED TO WASTE YOUR TIME ON THE ABOVE PARTS.

The final part goes:

Part E

With 500 VV across aa and bb, compute VcdVcd.

Express your answer in volts.

If you could direct me with normal text and not images on how to answer this final question

i would be very appericative and will throw possitive responses back :).

Thanks again.

Also will attempt to give you a image but no gaurentee and have the description above too.

Course Home
Syllabus
Scores
Pearson eText
Study Area
Document Sharing
User Settings
Course Tools
>
<CH 24
Problem 24.59
In (Figure 1), each capacitance C₁ is 6.6 µF, and each
capacitance C₂ is 4.4 μF.
Figure
a
b
C₁
C₂
C₁
C₁
C₂
C₁
C₁
-
C₁
U
1 of 1
Part A
Submit
Compute the equivalent capacitance of the network between points a and b.
Express your answer in farads.
Ceq 2.2x10-6 F
Correct
Part B
Previous Answers
Submit
<
Compute the charge on the capacitor C₁ nearest to a when Vab = 500 V.
Express your answer in coulombs.
Q₁ = 1.1×10-³ C
Previous Answers
Correct
8 of 14
Review | Constants
>
►

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Pulse Analog Modulation (Pulse Amplitude Modulation [PAM], Pulse Width Modulation [PWM], Pulse Position Modulation [PPM])

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions