### Transcription for Educational Website**Reaction Description:**A single alkyl bromide reactant theoretically yields either of the given products, depending on the reaction conditions. Draw the structure of the alkyl bromide compound.**Reaction Scheme:**1. **Product 1**: - Structure: A tertiary butyl group with an OCH₃ group attached. - Reaction: Alkyl bromide reacts with CH₃OH to form this product.2. **Alkyl Bromide**: The intermediate reactant in the given reaction scheme.3. **Product 2**: - Structure: A similar tertiary butyl group but with an OCH₃ group at a different position indicating an ether formation. - Reaction: Alkyl bromide reacts with CH₃O⁻ in DMSO with heat to form this product.**Instruction:**- **Task**: Draw the alkyl bromide. There is only one possible compound for this reactant.**Drawing Tool:**- **Options**: - Use drawing tools to sketch the structure. - Atomic options provided: C (carbon), H (hydrogen), Br (bromine). - Manipulate with tools to draw single, or double bonds as needed. - Additional features to add rings or more complex structures.**Controls:**- **Undo/Redo**: Buttons to step back or forward in changes.- **Zoom**: Options to enlarge or reduce the view of the drawing canvas for better visibility.This interactive module helps in practicing and understanding the concepts of organic reaction mechanisms and structural drawing of organic compounds.

The reaction of an alkyl halide with CH3OH proceeds with the SN1 reaction mechanism and the reaction of an alkyl halide with CH3O- in DMSO solvent proceeds by the SN2 reaction mechanism.The alkyl bromide formed in the given reaction is shown as follows, Thus, the alkyl bromide is,