### Organic Reaction PathwaysBelow is a flow diagram illustrating various organic reaction pathways. Each transformation involves specific reagents and conditions applied to a starting alkene to afford different products. This guide will help you understand how to predict the structure of the final products based on the given conditions.#### Reaction 1: #### Starting Compound: A molecule represented by a skeletal structure of a three-carbon chain with a double bond (alkene) attached to an isopropyl group. | Pathway 1: ||------------|**Reagent:** HBr- Draw the product of the reaction where HBr adds to the alkene. This typically follows Markovnikov's rule, where the bromine atom attaches to the more substituted carbon atom.**Reagent:** Cl₂, H₂O- Draw the product of the reaction where chlorine in the presence of water adds to the alkene. This follows anti-Markovnikov addition, where the chlorine atom and hydroxyl group add to the double bond in an anti-addition manner.#### Reaction 2: #### Starting Compound: A molecule represented by the same skeletal structure (a three-carbon chain with a double bond attached to an isopropyl group).| Pathway 2: ||------------|**Reagents:** 1. BH₃-THF 2. H₂O₂, NaOH- Draw the product of the hydroboration-oxidation reaction. This will result in an anti-Markovnikov addition of a hydroxyl group to the less substituted carbon atom of the double bond.**Reagents:** 1. O₃ 2. (CH₃)₂S- Draw the product of the ozonolysis reaction. Ozonolysis cleaves the double bond completely, producing two carbonyl-containing fragments.### Diagrams:Each box labeled "Select to Draw" is where the respective products of the reactions should be drawn. Follow the arrows to trace each reaction pathway:1. **Top Section:** - Select to draw the products for reactions with HBr or Cl₂/H₂O starting from the alkene.2. **Bottom Section:** - Select to draw the products for reactions with BH₃-THF followed by H₂O₂/NaOH, or for reactions with O₃ followed by (CH₃)₂S starting from the same alk ### Predict the Major Product of Alkene ReactionsA common alkene starting material is shown below. Predict the major product for each reaction. Ignore any inorganic byproducts.#### Diagram ExplanationThe main structure in the middle begins with an alkene (a molecule with a carbon-carbon double bond). This alkene starting material branches out to different reactions.1. **First Reaction Pathway:** - Reagent: **HBr** - **Select to Draw**: (Product of the reaction with HBr) 2. **Second Reaction Pathway:** - Reagents: **Cl₂, H₂O** - **Select to Draw**: (Product of the reaction with Cl₂ and H₂O) 3. **Third Reaction Pathway:** - Reagents: 1. **BH₃-THF** 2. **H₂O₂, NaOH** - **Select to Draw**: (Product of the Hydroboration-Oxidation reaction) 4. **Fourth Reaction Pathway:** - Reagents: 1. **O₃** 2. **(CH₃)₂S** - **Select to Draw**: (Product of the Ozonolysis reaction) #### Main Alkene Structure: CH3 | CH3-CH=CH-CH3To complete the task, you should predict the major organic product for each of the four reactions mentioned.---This educational page aims to provide a visual representation for predicting organic reaction products based on common alkene starting materials. Each reaction involves a different set of reagents, leading to specific transformations. By understanding these pathways, students can better grasp reaction mechanisms and product outcomes.

Answered: Image /qna-images/answer/aebb07db-d47b-46a5-8ffa-ac6c497974bf.jpg

Answered: Select to Draw HBr 1. BH3-THF 2. H2O2,…

Select to Draw HBr 1. BH3-THF 2. H2O2, NaOH Select to Draw d Select to Draw Cl₂ H₂O 1.03 2. (CH3)2S Select to Draw I I I I I

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

9. A 0.324 g sample of a compound undergoes combustion analysis and gives 1.095g CO₂ and 0.224g H₂O. A mass spectrum shows the molar mass to be 104g/mole. What is the molecular formula of this compound? A. C10H10 B. C₂H₂ C. C₂H4O (D) C8H8
: ny F1 ! Q What does a complete balanced chemical equation include? O F2 molar coefficients valence electrons exothermic coefficients 2 endothermic coefficients -0- @ W F3 -Ő+ #m 3 E F4 $ 4 F5 R % F6 T Q F7 6 Y F8 & 7 F9 *00 U 8 H
Jj.70.
17. Calculate the percent composition of C6H12O6 Group of answer choices a) 40% C , 53% O , 7 % H b) 25% C, 25% O, 50% H c) 35% C, 48% O, 17% H d) 10% C, 70% O, 20% H
4. How many grams of acetylene would be given off if the limiting reagent in the reaction is calcium carbide and you start with 2.00 g? fw CaC2 = 64.1 g/mol fw C2H2 = 26.0 g/mol BIIIU X2 | X² | → EEE Normal 5. Draw two resonance structures for benzene (C6H6). Upload an image (.heic or .jpg file) or your structures.
1- Suppose 5.0g of Compound A and 6.0g of Compound B are consumed in a reaction that produces only one product, Compound C. Calculate the theoretical yield of C. Round your answer to the nearest 0.1g. Suppose 7.4g of C are actually isolated at the end of the reaction. What is the percent yield of Compound C? Round your answer to the nearest whole percent. % 2- Solid phosphorus (P) and chlorine (Cl2) gas react to form solid phosphorus pentachloride (PCl5). Suppose you have 2.0 mol of P and 1.0 mol of Cl2 in a reactor. Calculate the largest amount of PCl5 that could be produced. Round your answer to the nearest 0.1 mol. _____mol 3-Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will form, enter its empirical formula in the last column. solution A solution B Does a precipitate form when A and B are mixed? the empirical formula of precipitate…
e) when a compound Containy e, H and 2 N's . Now, when we add two nitrogen atom we Should 2 CH2 unit (a). when a Compound Contaiy only c and H. thet meany C2 Hq urit mupt be elimate from the base formula, 136 = 10 +음 Nou, the mew formula Containing two nitrogen is - Accurding to the formula n=10 and r: 6 the base formula mupt be- Go HiD46 Ov, Cro Hia (d) when a Compound Containg c, H, 2NS and 20's when a Compound Contains e , H and 2 o's . Now, when we add two nitrogen and two orygen atom , we 2 CH4 and 2CH2 unit respectively, ) Now, when wse add two onygen atom Should elimimate 2 CHq unit that meanp G Hg unit myst eliminate from the hase formula. we Should that means we should elimimete C4 H2 unit from the base for mula . Now, the new formula Containig two onygen atom in Now, the new for mula Containing tawo nitrogen and two ozygen sn Cc HA Oz N2 6. Calculate the molecular formulas for possible compounds with molecular mass 136 using the Rule of 13. a. a compound that contains only C…
1. Consider the reaction: 3A + 5B + 1C – 2D + 1E THal C If you have 6 moles of reactant A and excess of B and C, how much product E would be formed? (Show your work).
2. MeCN n-BuLi; Et₂C=O Me- Me OH CN
What reactant would transform the molecule from the top left to the top right. Given the same molecule, what would the given reactants transform it into below?
__ Al(OH)3 + ___ HBr ------> ___ AlBr3 + ___ H2O Can yo balence this for me
A paper reports 1 mg of CH4-C. How do I convert and report this as 1 mg CH4 (includes molar mass of hydrogens)?