9. A 0.324 g sample of a compound undergoes combustion analysis and gives 1.095g CO₂ and 0.224g H₂O. A mass spectrum shows the molar mass to be 104g/mole. What is the molecular formula of this compound? A. C10H10 B. C₂H₂ C. C₂H4O C&Hs

9. A 0.324 g sample of a compound undergoes combustion analysis and gives 1.095g CO₂ and 0.224g H₂O. A mass spectrum shows the molar mass to be 104g/mole. What is the molecular formula of this compound? A. C10H10 B. C₂H₂ C. C₂H4O C&Hs

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Mass Spectrometry

This process is an instrumental method in which a sample is changed to fast moving positive ions by electron bombardment. The charged particles vary due to their different mass to charge ratio and are estimated with the help of this difference. It is also called mass spectroscopy.

Question

9. A 0.324 g sample of a compound undergoes combustion analysis and gives 1.095g CO₂ and
0.224g H₂O. A mass spectrum shows the molar mass to be 104g/mole. What is the molecular
formula of this compound?
A. C10H10
B. C₂H₂
C. C₂H4O
(D) C8H8

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