Br Br2 CH2CI2 H' H. Br H Electrophilic addition of bromine, Br2, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH2C1,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions H Br H- Br :Br: Prouioue Noxt

Br Br2 CH2CI2 H' H. Br H Electrophilic addition of bromine, Br2, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH2C1,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions H Br H- Br :Br: Prouioue Noxt

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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QUESTION 2 Answer the question below the reaction. O + Excess NH4C1 +H₂O In the second step of the reaction mechanism, which of the following is formed? CH3 CI H₂C O CI H₂C O OH H₂C CH3 H₂C CH3 U 34 CH3 CH3 CH3 CH3 H₂SO4 CH3 CI
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Draw curved arrows to show the movement of electrons in this step of the mechanism.
5. Even with excess cyanide present, only one equivalent will react with the following dibromoalkane. To which carbon with the cyanide add? Predict the product and explain your choice. Br H₂C H₂C CH3 Br CN DMSO
20) Propose reaction step(s) that would best accomplish the following conversions? OH O || || CH3CCH2CH H ? O || CH3CHCH2 CH OH CH3
The mechanism proceeds through a first cationic intermediate, intermediate 1. Nucleophilic attack leads to intermediate 2, which goes on to form the final product. In cases that involve negatively charged nucleophile, the attack of the nucleophile leads directly to the product. H. Br + CH3OH Br Intermediate 2 (product) Intermediate 1 In a similar fashion, draw intermediate 1 and intermediate 2 (final product) for the following reaction. OCH3 Cl2 MEOH ĆI racemic mixture Pay attention to the reactants, they may differ from the examples. In some reactions, one part of the molecule acts as the nucleophile. • You do not have to consider stereochemistry. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate intermediate 1 and intermediate 2 using the the dropdown menu. → symbol from
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The reaction in the box is missing a reagent/reactant... NCH3 NHCH3 Which of the following would you use to convert the starting material into the product in high yield? A) An oxidation reagent such as H2CrO4 B) A base such as NaOH/H20 C) An acid such as H2SO4 D) A reduction agent such as NABH4 A В C O D
Draw the missing reactant for the following reaction
In the acid catalyzed halogenation of ketones, what is the rate determining step? A. The first step: protonation of the ketone. B. The very last step in the mechanism, namely, loss of a hydrogen ion to form the product. C. Loss of a proton from the alpha-carbon of the protonated ketone to form an enol intermediate. D. Attachment of a halogen molecule to the enol intermediate.