Indicate the major organic product that would be formed under the conditions below: 1. ВН3 THF 2. NaOH, H,O2 Lon OH LBH2 C HO OH O O O O

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Chapter1: Chemical Foundations
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The image presents a chemical reaction question, which asks to identify the major organic product formed under specific conditions. The reactant is propene, represented as a three-carbon alkene with a double bond.

**Reagents and Conditions:**
1. BH₃·THF (Borane in Tetrahydrofuran)
2. NaOH, H₂O₂ (Sodium Hydroxide, Hydrogen Peroxide)

**Reaction Description:**
This is a hydroboration-oxidation reaction, a common method for converting alkenes to alcohols.

**Product Choices:**
Four structural options are provided for selection:
1. A primary alcohol with the hydroxyl group on the terminal carbon.
2. A secondary alcohol with the hydroxyl group on the middle carbon.
3. An organoborane intermediate with BH₂ attached to the terminal carbon.
4. A diol containing two hydroxyl groups.

The correct choice for this reaction is the primary alcohol, where the hydroxyl group is added to the less substituted carbon, illustrating anti-Markovnikov addition typical of hydroboration-oxidation reactions.
Transcribed Image Text:The image presents a chemical reaction question, which asks to identify the major organic product formed under specific conditions. The reactant is propene, represented as a three-carbon alkene with a double bond. **Reagents and Conditions:** 1. BH₃·THF (Borane in Tetrahydrofuran) 2. NaOH, H₂O₂ (Sodium Hydroxide, Hydrogen Peroxide) **Reaction Description:** This is a hydroboration-oxidation reaction, a common method for converting alkenes to alcohols. **Product Choices:** Four structural options are provided for selection: 1. A primary alcohol with the hydroxyl group on the terminal carbon. 2. A secondary alcohol with the hydroxyl group on the middle carbon. 3. An organoborane intermediate with BH₂ attached to the terminal carbon. 4. A diol containing two hydroxyl groups. The correct choice for this reaction is the primary alcohol, where the hydroxyl group is added to the less substituted carbon, illustrating anti-Markovnikov addition typical of hydroboration-oxidation reactions.
**Explanation of Reaction and Potential Major Products:**

In this exercise, we are asked to determine the major product of the given reaction, where a dibenzyl is exposed to osmium tetroxide (OsO₄) followed by sodium bisulfite (NaHSO₃) in water. This process typically results in the conversion of alkenes to diols by syn-dihydroxylation.

### Reaction Details:

- **Reagents:**
  1. **OsO₄** (Osmium tetroxide)
  2. **NaHSO₃, H₂O** (Sodium bisulfite in water)

- **Mechanism:**
  The osmium tetroxide adds to the double bond in a syn addition manner, leading to the formation of a cyclic osmate ester intermediate, which is subsequently hydrolyzed by sodium bisulfite to give a vicinal diol.

### Options for Major Products:

1. **Option 1:**
   - Structure: Two adjacent carbon atoms each bonded to a hydroxyl group, showing syn addition as both -OH groups are on the same side. Phenyl groups (Ph) are also present, indicating the presence of benzene rings.

2. **Option 2:**
   - Structure: Similar to option 1, with stereochemistry indicating syn addition but with different orientation. Phenyl groups are shown.

3. **Option 3:**
   - Structure: An epoxide ring is suggested here. This indicates a different pathway and is not the expected outcome with OsO₄.

4. **Option 4:**
   - Structure: Suggests the formation of an open chain with additional phenyl groups which is unlikely under these conditions.

5. **Option 5:**
   - Structure: Another epoxide, similar to option 3, which is less likely here.

6. **Option 6:**
   - Statement: No reaction under these conditions or the correct product is not listed.

### Conclusion:

- **Expected Outcome:**
  This reaction most likely leads to a syn-diol formation on the alkenes, specified in options 1 or 2. The reaction condition and reagents strongly support syn addition of hydroxyl groups.
Transcribed Image Text:**Explanation of Reaction and Potential Major Products:** In this exercise, we are asked to determine the major product of the given reaction, where a dibenzyl is exposed to osmium tetroxide (OsO₄) followed by sodium bisulfite (NaHSO₃) in water. This process typically results in the conversion of alkenes to diols by syn-dihydroxylation. ### Reaction Details: - **Reagents:** 1. **OsO₄** (Osmium tetroxide) 2. **NaHSO₃, H₂O** (Sodium bisulfite in water) - **Mechanism:** The osmium tetroxide adds to the double bond in a syn addition manner, leading to the formation of a cyclic osmate ester intermediate, which is subsequently hydrolyzed by sodium bisulfite to give a vicinal diol. ### Options for Major Products: 1. **Option 1:** - Structure: Two adjacent carbon atoms each bonded to a hydroxyl group, showing syn addition as both -OH groups are on the same side. Phenyl groups (Ph) are also present, indicating the presence of benzene rings. 2. **Option 2:** - Structure: Similar to option 1, with stereochemistry indicating syn addition but with different orientation. Phenyl groups are shown. 3. **Option 3:** - Structure: An epoxide ring is suggested here. This indicates a different pathway and is not the expected outcome with OsO₄. 4. **Option 4:** - Structure: Suggests the formation of an open chain with additional phenyl groups which is unlikely under these conditions. 5. **Option 5:** - Structure: Another epoxide, similar to option 3, which is less likely here. 6. **Option 6:** - Statement: No reaction under these conditions or the correct product is not listed. ### Conclusion: - **Expected Outcome:** This reaction most likely leads to a syn-diol formation on the alkenes, specified in options 1 or 2. The reaction condition and reagents strongly support syn addition of hydroxyl groups.
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