A simple random sample from a population with a normal distribution of 98 body temperatures has x= 98.40°F and s = 0.67°F. Construct a 95% confidence interval estimate of the standard deviation of body %3D temperature of all healthy humans. Click the icon to view the table of Chi-Square critical values. °F

A simple random sample from a population with a normal distribution of 98 body temperatures has x= 98.40°F and s = 0.67°F. Construct a 95% confidence interval estimate of the standard deviation of body %3D temperature of all healthy humans. Click the icon to view the table of Chi-Square critical values. °F

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The blood pressure (average of systolic and diastolic measurements) of each of 25 randomly selected persons was measured. The average was 97.5 mm Hg, and the standard deviation was 8.05 mm Hg. What is the critical t value? What is the margin of error?
Currently patrons at the library speak at an average of 64 decibels. Will this average change after the installation of a new computer plug in station? After the plug in station was built, the librarian randomly recorded 69 people speaking at the library. Their average decibel level was 61.7 and their standard deviation was 6. What can be concluded at the α = 0.05 level of significance? H0:H0: ? μ p Select an answer > ≠ < = H1:H1: ? p μ Select an answer = > < ≠ The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.)
Babies: A sample of 25 one-year-old girls had a mean weight of 24.1 pounds with a standard deviation of 4.3 pounds. Assume that the population of weights is normally distributed. A pediatrician claims that the standard deviation of the weights of one-year-old girls is greater than 7 pounds. Do the data provide convincing evidence that the pediatrician's claim is true? Use the =α0.05 level of significance.
In a sample of 12 randomly selected high school seniors, the mean score on a standardized test was 1182 and the standard deviation was 161.6.Further research suggests that the population mean score on this test for high school seniors is 1012. Does the t-value for the original sample fall between −t0.95 and t0.95? Assume that the population of test scores for high school seniors is normally distributed. What is The t-value? And does or does not it not fall between −t0.95 and t0.95 because t0.95=? (Round to two decimal places as needed.)
The mean pulse rate (beats per minute) of a random sample of 40 males was 67.3 bpm. For a random sampl of 40 females the mean was 77.5 bpm. The population standard deviation for males is 10.3 bpm and 11.6 bpm for females. Using the P-Value method and test the claim that there is a difference in mean pulse rates. Use alpha = 0.03. Step 5: There is enough evidence to reject the claim that there is a difference in pulse rates for males and females. O There is enough evidence to support the claim that there is a difference in pulse rates for males and females. There is not enough evidence to reject the claim that there is a difference in pulse rates for males and females. There is not enough evidence to support the claim that there is a difference in pulse rates for males and females. SAMSUNG 女 & 4 5 7 8 r t y %24
An obstetrician read that a newborn baby loses on average 7 ounces in the first two days of his or her life. He feels that in the hospital where he works, the average weight loss of a newborn baby is less than 7 ounces. A random sample of 33 newborn babies has a mean weight loss of 6.2 ounces. The population standard deviation is 1.5 ounces. Is there enough evidence at =α0.01 to support his claim? Assume that the variable is normally distributed. Use the P -value method with tables. hello there are five parts to the question it asks to state the hypothessis and identify the claim it asks to compute the test value find the p value and choose the null hypothesis
An obstetrician read that a newborn baby loses on average 7 ounces in the first two days of his or her life. He feels that in the hospital where he works, the average weight loss of a newborn baby is less than 7 ounces. A random sample of 30 newborn babies has a mean weight loss of 6.4 ounces. The population standard deviation is 1.6 ounces. Is there enough evidence at =α0.01 to support his claim? Assume that the variable is normally distributed. Use the critical value method with tables. hello the question askas to find the critical value compute the test value and select the hypothesis
A random sample of 15 exam scores showed a standard deviation of 6.0 points. Find the 95 percent confidence interval for the population standard deviation. Use Appendix E to obtain the values of χ2LχL2 and χ2UχU2 . (Round your answers to 2 decimal places.) The 95% confidence interval is from ______ to __________ .
During an economic crisis, the average value of homes in a community of 36 homes lost $9445 with a standard deviation of $1300. The average home value in the region lost $8990. Was this community of 36 homesunusual? Use a t-test to decide if the average loss observed was significantly different from the region value. Use a level of significance α=0.05. Identify the hypotheses for the test. H0: μ ▼ not equals≠ equals= greater than> less than< nothing HA: μ ▼ equals= greater than> not equals≠ less than< nothing The test statistic is nothing. (Round to two decimal places as needed.) The P-value is nothing. (Round to three decimal places as needed.) What is the conclusion of the test? Was the average loss observed significantly different from the region value? ▼ Reject Fail to reject the null hypothesis because the P-value is ▼ greater less than the given significance level, and conclude that the…
The random sample of n=75�=75 yielded a sample mean of x¯=26�¯=26.Assume that we know the population standard deviation is σ=30�=30. Step 2 of 3 : Calculate a 95% confidence interval for the population mean. Round your answers to 2 decimals places.
A simple random sample from a population with a normal distribution of 99 body temperatures has x = 98.80°F and s= 0.61°F. Construct a 98% confidence interval estimate of the standard deviation of body temperature of all healthy humans. Click the icon to view the table of Chi-Square critical values. °F
A simple random sample from a population with a normal distribution of 107 body temperatures has x = 98.10°F and s = 0.61°F. Construct a 98% confidence interval estimate of the standard deviation of body temperature of all healthy humans. Click the icon to view the table of Chi-Square critical values. °F