A simple random sample from a population with a normal distribution of 102 body temperatures has x = 98.40°F and s= 0.65°F. Construct a 95% confidence interval estimate of the standard deviation of body temperature of all healthy humans. Click the icon to view the table of Chi-Square critical values. °F

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**Constructing a 95% Confidence Interval for Standard Deviation**

A simple random sample from a population with a normal distribution of 102 body temperatures has a sample mean (\(\bar{x}\)) of 98.4°F and a sample standard deviation (\(s\)) of 0.65°F. The task is to construct a 95% confidence interval estimate of the standard deviation of body temperature for all healthy humans.

To proceed:

- **Click the icon** to view the table of Chi-Square critical values.

**Confidence Interval Calculation**

\[ 
\sqrt{\frac{(n-1)s^2}{\chi^2_{\text{right}}}} < \sigma < \sqrt{\frac{(n-1)s^2}{\chi^2_{\text{left}}}}
\]

- **Degrees of Freedom (df)**: \( n - 1 = 102 - 1 = 101 \)

**Enter the Interval:**

\[ \_\_^\circ F < \sigma < \_\_^\circ F \]

*(Round to two decimal places as needed.)*
Transcribed Image Text:**Constructing a 95% Confidence Interval for Standard Deviation** A simple random sample from a population with a normal distribution of 102 body temperatures has a sample mean (\(\bar{x}\)) of 98.4°F and a sample standard deviation (\(s\)) of 0.65°F. The task is to construct a 95% confidence interval estimate of the standard deviation of body temperature for all healthy humans. To proceed: - **Click the icon** to view the table of Chi-Square critical values. **Confidence Interval Calculation** \[ \sqrt{\frac{(n-1)s^2}{\chi^2_{\text{right}}}} < \sigma < \sqrt{\frac{(n-1)s^2}{\chi^2_{\text{left}}}} \] - **Degrees of Freedom (df)**: \( n - 1 = 102 - 1 = 101 \) **Enter the Interval:** \[ \_\_^\circ F < \sigma < \_\_^\circ F \] *(Round to two decimal places as needed.)*
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