A simple random sample from a population with a normal distribution of 108 body temperatures has x = 98.10°F ands=0.64°F. Construct a 90% confidence interval estimate of the standard deviation of body temperature of all healthyhumans.Click the icon to view the table of Chi-Square critical values.°F

Sample size(n)=108 Sample mean(x¯)=98.10 Sample standard deviation(s)=0.64 degrees of…

Answered: A simple random sample from a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A sample of 14 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The mean weight was 2 ounces with a standard deviation of 0.12 ounces. The population standard deviation is known to be 0.1 ounce. x = σ = sx = n = n − 1 =
Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find Pg9, the 69-percentile. This is the temperature reading separating the bottom 69% from the top 31%. P69 = °C
Attenuation is the reduction of the amplitude of a signal, electric current, or other oscillation. With maximum attenuation, a scanner will not be able to read a bar code at a fixed distance. After substantial amount of data collection, a group of instrumentation engineers decided to model a variation of maximum attenuation of scanners as a normal distribution with a mean of 10.1 decibels and standard deviation of 2.7, same unit. What proportion of the products have maximum attenuation greater than 15.1 dB? 0.0718 none of these 0.0322 0.0214
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1522 and the standard deviation was 311. The test scores of four students selected at random are 1950, 1260, 2190, and 1410. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The z-score for 1950 is. (Round to two decimal places as needed.)
Assume that the mean height of men in the United States is 70 inches, with a standard deviation of 3 inches. A particular man is 80 inches tall. Find the z-score of his height. (Round to two decimal places.)
Calcium levels in people are normally distributed with a mean of 9.7 mgdL and a standard deviation of 0.5 mgdL . Individuals with calcium levels in the bottom 10% of the population are considered to have low calcium levels. Find the calcium level that is the borderline between low calcium levels and those not considered low. Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.
Suppose we have only ten scores representing the ages (in years) of randomly selected U.S. commercial aircraft. The average age of the ten aircraft is 14.25 years and the sample standard deviation is 9.349 years. Construct a 95% confidence interval for the mean age of all U.S. commercial aircraft. I would appreciate to see what formulas you use and the work through because I messed up.
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1458 and the standard deviation was 312. The test scores of four students selected at random are 1860, 1220, 2150, and 1340. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The z-score for 1860 is (Round to two decimal plaes as needed.)
A manufacturer of light bulbs finds that one light bulb model has a mean life span of 1025 h with a standard deviation of 83 h.Find the z-scores for lightbulbs which last 850 and 900 h. (Round your answers to two decimal places.) 850 h: z = 900 h: z =
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P87, the 87-percentile. This is the temperature reading separating the bottom 87% from the top 13%.P87 = °C
An experiment is being conducted to see if one type of animal feed is better than another. The experiment used 120 animals. The weight of the animals was a mean of 70.05 kg with the new food vs 66.61 with the current food being used. The standard deviation of the samples was 11.16lbs. Write your hypotheses in statistics form. Attached is a table of T values. Determine if the new food is contributing to larger weight. Assume an alpha 10%. What would you conclude about the new feed if the alpha were 5%

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