A simple pendulum of length L= 1.87 m is released from rest from a position making an angle of 9° with respect to the equilibrium position. Determine the %3D pendulum's linear velocity when it passes through the angular position 0 = 6°. (g = 9.8 m/s^2) %3D O v = t0.6 m/s O v = 10.7 m/s O v = ±0.4 m/s O v = +0.3 m/s O v = 10.8 m/s Ov= 10.5 m/s
A simple pendulum of length L= 1.87 m is released from rest from a position making an angle of 9° with respect to the equilibrium position. Determine the %3D pendulum's linear velocity when it passes through the angular position 0 = 6°. (g = 9.8 m/s^2) %3D O v = t0.6 m/s O v = 10.7 m/s O v = ±0.4 m/s O v = +0.3 m/s O v = 10.8 m/s Ov= 10.5 m/s
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![A simple pendulum of length L = 1.87 m is released from rest from a position
making an angle of 9° with respect to the equilibrium position. Determine the
pendulum's linear velocity when it passes through the angular position 0 = 6°. (g
= 9.8 m/s^2)
O v = t0.6 m/s
O v = +0.7 m/s
O v = +0.4 m/s
O v = +0.3 m/s
O v = +0.8 m/s
O v = =0.5 m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb60ce3ee-12a9-4276-ab09-1d857b959e4f%2F9a766d5f-5fa3-48f6-928a-e9b4ac99741f%2Fx99s9jm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A simple pendulum of length L = 1.87 m is released from rest from a position
making an angle of 9° with respect to the equilibrium position. Determine the
pendulum's linear velocity when it passes through the angular position 0 = 6°. (g
= 9.8 m/s^2)
O v = t0.6 m/s
O v = +0.7 m/s
O v = +0.4 m/s
O v = +0.3 m/s
O v = +0.8 m/s
O v = =0.5 m/s
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