A semiconductor material with k = 2 W/m.K and electric resistivity, r =2x10-5 W.m, is used to fabricate a cylindrical rode 40 mm long with a diameter of 10 mm. The longitudinal surface of the rod is well insulated and may be considered adiabatic while the ends are maintained at temperatures 100C and 0C, respectively. If the rod carries a current of 10 amps, what will be its midpoint temperature? What will be the rate of heat transfer through both ends?
A semiconductor material with k = 2 W/m.K and electric resistivity, r =2x10-5 W.m, is used to fabricate a cylindrical rode 40 mm long with a diameter of 10 mm. The longitudinal surface of the rod is well insulated and may be considered adiabatic while the ends are maintained at temperatures 100C and 0C, respectively. If the rod carries a current of 10 amps, what will be its midpoint temperature? What will be the rate of heat transfer through both ends?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A semiconductor material with k = 2 W/m.K and electric resistivity, r =2x10-5 W.m, is used to fabricate a cylindrical rode 40 mm long with a diameter of 10 mm. The longitudinal surface of the rod is well insulated and may be considered adiabatic while the ends are maintained at temperatures 100C and 0C, respectively. If the rod carries a current of 10 amps, what will be its midpoint temperature? What will be the rate of heat transfer through both ends?
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Step 1
Given:
Thermal conductivity of material
Electric resistivity
Length of rod
The diameter of rod
The temperature at first end
The temperature at second end
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