A second-order reaction has a rate constant of 9.7 × 10 /(M • s) at 30.°C. At 40.°C, the rate constant is 3.1 × 10-3 /(M • s). What are the activation energy and frequency factor for this reaction? Predict the value of the rate constant at 45°C. Activation energy = | kJ/mol Frequency factor· /(M • s) Rate constant /(M · s)
A second-order reaction has a rate constant of 9.7 × 10 /(M • s) at 30.°C. At 40.°C, the rate constant is 3.1 × 10-3 /(M • s). What are the activation energy and frequency factor for this reaction? Predict the value of the rate constant at 45°C. Activation energy = | kJ/mol Frequency factor· /(M • s) Rate constant /(M · s)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A second-order reaction has a rate constant of 9.7 x 104
/(M · s) at 30.°C. At 40.°C, the rate constant is 3.1 x 10-3
|(M - s). What are the activation energy and frequency
factor for this reaction? Predict the value of the rate constant
at 45°C.
Activation energy
|kJ/mol
Frequency factor =
/(M · s)
/(M - s)
Rate constant =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F97e1b17f-72c5-4bfa-9560-03b6b866a058%2F66b0ff59-62ec-4b82-93b3-6e81c9aade7b%2Fl4e6vr5_processed.png&w=3840&q=75)
Transcribed Image Text:A second-order reaction has a rate constant of 9.7 x 104
/(M · s) at 30.°C. At 40.°C, the rate constant is 3.1 x 10-3
|(M - s). What are the activation energy and frequency
factor for this reaction? Predict the value of the rate constant
at 45°C.
Activation energy
|kJ/mol
Frequency factor =
/(M · s)
/(M - s)
Rate constant =
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