Consider the combustion of ethane: 2C₂H6 (9) +702(g) → 4 CO2 (g) + 6H₂O(g) If the ethane is burning at the rate of 0.8 mol/L x s, at what rates are CO₂ and H₂O being produced? CO₂ = mol/L x s H₂O = mol/L x s
Consider the combustion of ethane: 2C₂H6 (9) +702(g) → 4 CO2 (g) + 6H₂O(g) If the ethane is burning at the rate of 0.8 mol/L x s, at what rates are CO₂ and H₂O being produced? CO₂ = mol/L x s H₂O = mol/L x s
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Chapter1: Chemical Foundations
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![**Combustion of Ethane**
Consider the combustion of ethane:
\[ 2\text{C}_2\text{H}_6(g) + 7\text{O}_2(g) \rightarrow 4\text{CO}_2(g) + 6\text{H}_2\text{O}(g) \]
If the ethane is burning at the rate of 0.8 mol/L × s, at what rates are CO\(_2\) and H\(_2\)O being produced?
- CO\(_2\) = [ ] mol/L × s
- H\(_2\)O = [ ] mol/L × s
**Explanation:**
This chemical equation represents the complete combustion of ethane (\(\text{C}_2\text{H}_6\)) in the presence of oxygen (\(\text{O}_2\)) to produce carbon dioxide (\(\text{CO}_2\)) and water (\(\text{H}_2\text{O}\)).
To determine the rates of production of CO\(_2\) and H\(_2\)O, use the stoichiometry of the reaction:
- According to the reaction, 2 moles of \(\text{C}_2\text{H}_6\) yield 4 moles of \(\text{CO}_2\). Therefore, if \(\text{C}_2\text{H}_6\) is being consumed at 0.8 mol/L × s, \(\text{CO}_2\) is produced at \(0.8 \times \frac{4}{2} = 1.6\) mol/L × s.
- Similarly, 2 moles of \(\text{C}_2\text{H}_6\) yield 6 moles of \(\text{H}_2\text{O}\), leading to a rate of \(0.8 \times \frac{6}{2} = 2.4\) mol/L × s for \(\text{H}_2\text{O}\).
**Final Rates:**
- \(\text{CO}_2\) = 1.6 mol/L × s
- \(\text{H}_2\text{O}\) = 2.4 mol/L × s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F216d8975-823a-443e-8abc-06f056adfa09%2F94d0c453-c353-4850-9a7f-30473630c15e%2Fmp0479d_processed.png&w=3840&q=75)
Transcribed Image Text:**Combustion of Ethane**
Consider the combustion of ethane:
\[ 2\text{C}_2\text{H}_6(g) + 7\text{O}_2(g) \rightarrow 4\text{CO}_2(g) + 6\text{H}_2\text{O}(g) \]
If the ethane is burning at the rate of 0.8 mol/L × s, at what rates are CO\(_2\) and H\(_2\)O being produced?
- CO\(_2\) = [ ] mol/L × s
- H\(_2\)O = [ ] mol/L × s
**Explanation:**
This chemical equation represents the complete combustion of ethane (\(\text{C}_2\text{H}_6\)) in the presence of oxygen (\(\text{O}_2\)) to produce carbon dioxide (\(\text{CO}_2\)) and water (\(\text{H}_2\text{O}\)).
To determine the rates of production of CO\(_2\) and H\(_2\)O, use the stoichiometry of the reaction:
- According to the reaction, 2 moles of \(\text{C}_2\text{H}_6\) yield 4 moles of \(\text{CO}_2\). Therefore, if \(\text{C}_2\text{H}_6\) is being consumed at 0.8 mol/L × s, \(\text{CO}_2\) is produced at \(0.8 \times \frac{4}{2} = 1.6\) mol/L × s.
- Similarly, 2 moles of \(\text{C}_2\text{H}_6\) yield 6 moles of \(\text{H}_2\text{O}\), leading to a rate of \(0.8 \times \frac{6}{2} = 2.4\) mol/L × s for \(\text{H}_2\text{O}\).
**Final Rates:**
- \(\text{CO}_2\) = 1.6 mol/L × s
- \(\text{H}_2\text{O}\) = 2.4 mol/L × s
![A first-order reaction has rate constants of \(4.6 \times 10^{-2} \, \text{s}^{-1}\) and \(8.9 \times 10^{-2} \, \text{s}^{-1}\) at 0°C and 20°C, respectively. What is the value of the activation energy?
Activation energy = [ ] kJ/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F216d8975-823a-443e-8abc-06f056adfa09%2F94d0c453-c353-4850-9a7f-30473630c15e%2F4860bch_processed.png&w=3840&q=75)
Transcribed Image Text:A first-order reaction has rate constants of \(4.6 \times 10^{-2} \, \text{s}^{-1}\) and \(8.9 \times 10^{-2} \, \text{s}^{-1}\) at 0°C and 20°C, respectively. What is the value of the activation energy?
Activation energy = [ ] kJ/mol
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