The decomposition reaction of NO 2 is important in atmospheric chemistry. The reaction 2NO 2(g) → 2NO(g) + O 2(g) is second order with respect to NO 2. How can the rate constant be determined? A plot of 1/[NO2] versus time will be linear with a slope of -k. A plot of 1/[NO2] versus time will be linear with a slope of k. A plot of [NO2] versus time will be linear with a slope of -k. A plot of In[NO2] versus time will be linear with a slope of -k. Click Save and Submit to save and submit. Click Save All Answers to save all answers.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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**Question 13**

The following graphs can be used for the questions that follow:

**Graph Descriptions:**

1. **First Graph:**
   - **Axes:** y-axis labeled as \([\text{N}_2\text{O}_5]\), x-axis labeled as time (min).
   - **Line Description:** The graph shows a downward-sloping curve, indicating a decrease in \([\text{N}_2\text{O}_5]\) concentration over time.

2. **Second Graph:**
   - **Axes:** y-axis labeled as \([\text{N}_2\text{O}_5]\), x-axis labeled as time (min).
   - **Line Description:** The graph has a linear relationship with the equation \(y = -0.0356x + 0.1058\), suggesting a straight-line trend in the graph.
   - **Note:** The line is marked as "Linear (Set 4)" in the legend.

**Chemical Reaction Details:**

The decomposition reaction of NO\(_2\) is important in atmospheric chemistry. The reaction is as follows:

\[2\text{NO}_2(g) \rightarrow 2\text{NO}(g) + \text{O}_2(g)\]

**Question:**

The reaction is second order with respect to NO\(_2\). How can the rate constant be determined?

- A plot of \(1/\text{[NO}_2]\) versus time will be linear with a slope of -k.
- A plot of \(\ln[\text{NO}_2]\) versus time will be linear with a slope of -k.
- A plot of \([\text{NO}_2]\) versus time will be linear with a slope of -k.
- A plot of \([\text{ln[NO}_2]\) versus time will be linear with a slope of -k.

**Instructions:**

Click "Save and Submit" to save and submit. Click "Save All Answers" to save all answers.
Transcribed Image Text:**Question 13** The following graphs can be used for the questions that follow: **Graph Descriptions:** 1. **First Graph:** - **Axes:** y-axis labeled as \([\text{N}_2\text{O}_5]\), x-axis labeled as time (min). - **Line Description:** The graph shows a downward-sloping curve, indicating a decrease in \([\text{N}_2\text{O}_5]\) concentration over time. 2. **Second Graph:** - **Axes:** y-axis labeled as \([\text{N}_2\text{O}_5]\), x-axis labeled as time (min). - **Line Description:** The graph has a linear relationship with the equation \(y = -0.0356x + 0.1058\), suggesting a straight-line trend in the graph. - **Note:** The line is marked as "Linear (Set 4)" in the legend. **Chemical Reaction Details:** The decomposition reaction of NO\(_2\) is important in atmospheric chemistry. The reaction is as follows: \[2\text{NO}_2(g) \rightarrow 2\text{NO}(g) + \text{O}_2(g)\] **Question:** The reaction is second order with respect to NO\(_2\). How can the rate constant be determined? - A plot of \(1/\text{[NO}_2]\) versus time will be linear with a slope of -k. - A plot of \(\ln[\text{NO}_2]\) versus time will be linear with a slope of -k. - A plot of \([\text{NO}_2]\) versus time will be linear with a slope of -k. - A plot of \([\text{ln[NO}_2]\) versus time will be linear with a slope of -k. **Instructions:** Click "Save and Submit" to save and submit. Click "Save All Answers" to save all answers.
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