A screen is placed a distance d = 41.0 cm to the right of a small object. At what two distances to the right of the object can a converging lens of focal length +6.55 cm be placed if the real image of the object is at the location of the screen?(Hint: Use the thin lens equation in the form s' =sfS-fshorter distancelonger distancecmcm"so s'(sf) = sf. Write s' = d -s and solve for s in the resulting quadratic equation.)For this lens, what is the smallest value d can have and an image be formed on the screen?cm

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Answered: A screen is placed a distance d = 41.0…

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