A screen is placed a distance d = 41.0 cm to the right of a small object. At what two distances to the right of the object can a converging lens of focal length +6.55 cm be placed if the real image of the object is at the location of the screen? sf (Hint: Use the thin lens equation in the form s' = s-f so s'(s-f) = sf. Write s'=d-s and solve for s in the resulting quadratic equation.) shorter distance longer distance cm cm For this lens, what is the smallest value d can have and an image be formed on the screen?
A screen is placed a distance d = 41.0 cm to the right of a small object. At what two distances to the right of the object can a converging lens of focal length +6.55 cm be placed if the real image of the object is at the location of the screen? sf (Hint: Use the thin lens equation in the form s' = s-f so s'(s-f) = sf. Write s'=d-s and solve for s in the resulting quadratic equation.) shorter distance longer distance cm cm For this lens, what is the smallest value d can have and an image be formed on the screen?
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Transcribed Image Text:A screen is placed a distance d = 41.0 cm to the right of a small object. At what two distances to the right of the object can a converging lens of focal length +6.55 cm be placed if the real image of the object is at the location of the screen?
(Hint: Use the thin lens equation in the form s' =
sf
S-f
shorter distance
longer distance
cm
cm
"
so s'(sf) = sf. Write s' = d -s and solve for s in the resulting quadratic equation.)
For this lens, what is the smallest value d can have and an image be formed on the screen?
cm
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